Setting up a Double Integral Using Both Orders of Integration

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This videos shows the setup of 3 double integrals using both orders of integration. Two are bounded by curves and the third example is a triangular region.
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the is the clearest example on the internet. this video should be recommended first.

youneszahr
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Exactly what I needed, efficient and straight to the point. Also, a MASSIVE thank you for the closed captions!

guitargeek
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Actually from 0 to 1, y=x^3 would be below y=x^2. If we consider x=1/2
(1/2)^3 = 1/8 and (1/2)^2 = 1/4. 1/8 is less than 1/4 so y=x^3 would be below y=x^2. I hope that makes sense. However, after x = 1, y=x^3 would be above y = x^2. I'm glad you find the videos helpful!

Mathispoweru
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Clearest and best examples on youtube. Thanks for all the hard work you do.

Frank_The_Tank
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This was great. I'm taking two different classes that use this stuff, and both classes just kind of brushed over it. It's really helpful to spend even just 10 minutes going through examples. THANK YOU!

GuppyPal
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I yook your online classes at Phoenix College for Calc I-III. I am now a senior EE student at ASU and just want to say that your videos are still the best reference material for when I need to refresh on Calculus topics. Thank you!

Caleb-mfcp
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Loved the last example in particular! You're awesome!

Blossoms
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Thank you! My professor didn't elaborate how we had to go from left to right when obtaining the lower and higher bounds of the integral with respect to x. It explains a lot, thanks!

Lexyvil
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Thank you, darling! That is just the kind of knowledge and detail that I need for my studies. You're the best!

Blossoms
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the best one explaining double integral, goat

steveying
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Thank you for helping me understand this aspect of multivariate calculus

ronaldjensen
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Been looking for this kind of explanation, thank you for this,

glydelcabale
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oh yeah, this is what i've been looking for. thank you.

winner
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best tut in yt for finding limits Thumbs up

xiii
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Hey there! What if the problem gives a region but not a explicit function to use (like f(x, y)=(x+y))?

caioc
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You, my friend, are awesome. Thank you.

bobbobby
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You mislabeled the graphs. y= x^2 is the outside curve, not the inside curve. Remember the graph of x^3 increases faster than the y= x^2 graph so it is more narrow.

I love your videos, and thanks a million for them.

Blossoms
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Liked and subscribed. Very efficient and well organized thought.

phannguyen
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when you changed the integration how did you see that sq root of y is the lower limit . your graph did not change? am very confused please help

thanks

halhauder
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Thank you so much this really helped me a lot!

eggxecution