Physics: Basic Statics w/ Ladders

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A 20 kg uniform ladder 2.5 meters long rests against a smooth wall at an angle of 53 degrees with the horizontal. Calculate the Forces on the ladder exerted by the floor and the wall.

Stephan Pichardo

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Thank YOU!!.. this video was PERFECT from Beginning to End!!.. I think it's safe to say that even a 5th grader could have learned from this.. :) .. You are very Clear and stepwise methodical.. and that's what WORKS.. :) .. thanks again...

ptyptypty

Thank you so much! this was so helpful. I was thinking that we were going to resolving the triangle into its x and y components. you got yourself a new subscriber. keep up the good work man!

AkpunkuDaniel

Thank you very much for this excellent explanation.

valeriereid

I got confused with the FN. Why you did not consider the force acting on x-Axis at that point since the ladder stands inclined to the ground. (other than Fs). That should be FNy and FNx, right?

fatihtekin

The coordinate system you used here is weird for me, why do you take the cos component for the gravitational force of the ladder instead of the sin component, and the sin component for the normal force? To me, coordinate system you set here, implies that you take the sin component of gravity (since it acts downwards) and the cos component of the normal force (since it acts to the right)

Kruzeda

why is the horizontal gravitational force not a part of the horizontal forces?

sha

why did u use fg and fw as the forces in the torque equation

fisherofmen

how did you calculate the Fw? at the last part

abrainttadeo

How the heck is the y component perpendicular to the ladder, it isn’t lol…this makes no sense and how is the x component of the fg force perpendicular to the ladder cause it isn’t either …like what

TripleAceAAA

why don't you just use 2.5sin(53) to find the perpendicular radius to the force of the wall, and then divide 2.5 by 2 and do 1.25cos(53) to find the perpindulcar radius to the force of the ladder. would that be incorrect? it seems much easier to me

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