Ace Probability in March Attempt!! | JEE Maths | JEE 2021 | Shimon Sir | Vedantu JEE Enthuse English

Ace Probability in March Attempt!! (JEE Mains 2021) | JEE Maths 2021 (JEE 2021) #VedantuJEEEnthuseEnglish​ with your favourite Shimon Sir. Ace Probability in March Attempt session will help you to get more marks in JEE Maths. You can now watch today's session of Ace Probability | Probability JEE One Shot | Probability for IIT JEE Mains 2021 | Probability for JEE Mains 2021 | Probability IIT JEE 2021 | Probability JEE Maths | Probability Math (Probability JEE Mains Vedantu).

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➡️ Topics Covered in this Session:
♦ Ace Probability
♦ Probability for JEE Mains Maths
♦ Probability JEE (JEE probability)
♦ Probability JEE Mains 2021
♦ Probability JEE One Shot (Probability IIT JEE Maths)
♦ Probability for IIT JEE Mains 2021
♦ JEE English Online Classes
♦ Online Classes for JEE

🎯 Vedantu JEE Enthuse (English) online class - Learn every detail of today’s topic Questions of Ace Probability | Probability JEE One Shot | Probability for IIT JEE Mains 2021 | Probability for JEE Mains 2021 | Probability IIT JEE 2021 | Probability JEE Maths | Probability Math (Probability JEE Mains Vedantu) | JEE English Online Classes | Online Coaching for IIT JEE | Online Classes for JEE | Vedantu JEE Enthuse English.

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#ProbabilityJEE #JEEMain2021 #JEEMaths #JEE2021 #JEE #JEEPreparation #ShimonSirVedantu #OnlineJEECoaching #JEEEnglish #VOTE #comeback

Let us know if you come across any doubts 🤔 in today's Session "Ace Probability in March Attempt!! " (JEE Mains 2021) (JEE Maths) by Shimon Sir. #withme #learningwontstop

[radhaabburi]

Sir.... I am not worried about results...bcoz i believe that I will get for wt i did.... But calls from relatives and their words are worrying me alot.... That making to loose hope and feel somewhat depressed 😔😔

[mamtaroy]

I registered only for Jee Mains February attempt
Do I need to register as a new candidate for March attempt or shall I apply using the old application number

[Saitama-pydz]

sir homework question: nC9 = nC7 so n = 16 and probability of getting 2 heads from 16 times is 16C2 x (1/2)^2 x (1/2)^14 = 16C2 x (1/2)^16 hence the option is 1

[vladimirputin]

It was a great session sir! Thank you so much for giving all these for free😀

[rishiv]

29:45 got it? this is the way you do it. do you all like it?
lol nice sir

[AmanKumar-wbht]

Sir you didn't take 25 Feb shift 1 questions. Please do it in another video sir.😭

[Happy-lxsc]

Can this be a bonus?
The question says area bounded by curves y=||x-1|-2|

It's no where mentioned x axis
70819120006 is the question id
Shift 1 Feb 26