Conservation of Linear Momentum (Learn to solve any problem)

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Learn about the conservation of momentum through animated examples, step by step.

Introduction(00:00)
The 30-Mg freight car A and 15-Mg freight car B...(00:52)
The 20-g bullet is traveling at 400 m/s when it becomes embedded...(02:56)
Block A has a mass of 5 kg and is placed on the smooth triangular block B...(06:14)

Learn about these topics before understanding conservation of momentum:

Book used: R. C. Hibbeler and K. B. Yap, Mechanics for engineers - dynamics. Singapore: Pearson Education, 2014.
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At 4:27, there is a typo. The acceleration should be negative in that step, since we picked up to be positive. However, the next step is correct and this does not affect the final answer.

QuestionSolutions
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This deserves a million views. Thanks a lot, Sir!

eksp.
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You are by far the best dynamics online instructor I've found! your videos are simple to understand and tackle some hard problems. PLEASE keep up the great work you're amazing!!

aidenbrown
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I finished Dynamics! This channel did help me!

joshuacharlery
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I am almost done my first year of engineering and would like to thank you for getting me through dynamics :D

jadkhalil
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This is my favorite channel to prepare for exams! Please do lots more example videos on work, conservation of energy, and impulse and momentum

jaycivandehey
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The work that is done on these video is unreal, keep it up :)

exotic
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For question 2, if anyone finds it challenging to identify the integrals, I found that using the work-energy method is more intuitive. It avoids dealing with integrals and is simplified as:
1/2(Ma+Mb)(v)^2 - (N)(k)(s) = 0
and solve for s

Tund_
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@4:27 when you calculate the normal force N, you said that upwards was positive so I think the equation would have been N(t) - 9.81(2.02)(t) = 0.

vn
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hey guys In 2:56 question, if you use work energy principle then it will be far more easier. T1+U=T2 (;T2=0) we have all value except the distance traveled, easy!
Also thanks to you I can pass my dynamic exam.

Ankit-
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this is so clear and helpful, thank you!

thenellecornejo
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I never really comment but Damn! This is perfect, I was searching for this kinda channel, thankyou for clearing all our doubts! Loads of love ❤️❤️❤️❤️❤️

siddhirajput
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love to watch your videos thankyou for creating such a nice content for students that struggling in their studies hope to see more videos like these thankyou buddy again

BhrweBhrwe
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On the last problem at 7:25, I think it should be V a/b because we know from B's perspective A moved .5 meters. We don't know yet what b/a is. If we get it wrong in a case would it make a difference if we keep our signs correct? I can't figure that out. Thanks for your hard work.

rk
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thanks a lot for this video, GOD Bless

wilordsanmiguel
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Thanks so much for posting these!

A question about the second question. I used the equations of motion in y to find the Frictional force, then I used them again in x to find acceleration. Plugged it into the kinematic equation a ds = v dv, integrated and solved. I got the correct answer but I was wondering if it's another valid method or just a fluke. Thanks again!

alaukwuanozie
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3:43 We can also determine the distance using energy method right? Rather than determining the time (t).

viralcat-wx
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Very nice pedagogy and all concepts in a nutshell

JyotiSingh-onml
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Bro, really you are so amazing thank you ❤

qusiaamer
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For the bullet block problem. wouldn't it be much easier to use work energy principle?

sakn