Resistors In Parallel - The Easy Way!

This physics video tutorial provides a basic introduction into parallel circuits. it explains how to calculate the electric current flowing through each resistor in a parallel circuit. The voltage across each resistor is the same in a parallel circuit and it's equal to the voltage of the battery. This tutorial explains how to solve parallel circuits with two resistors and with three resistors. It discusses how to calculate the power delivered by the battery to the circuit and the power absorbed by each resistor. Kirchoff's current law applies to parallel circuits which states that the total current entering a junction must equal to the total current leaving the junction - this is also known as the junction rule of kirchoff's law. This video uses the principles behind ohm's law to calculate the voltage, current, resistance, and power of an element or device in a circuit.

Schematic Diagrams & Symbols:

Resistors In Series:

Series and Parallel Circuits - Light Bulb Brightness:

Equivalent Resistance of Complex Circuits:

How To Solve DC Circuits:

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Voltage Divider Circuit:

Current Dividers:

Parallel Circuit Challenge Problem:

Kirchhoff's Current Law:

Kirchhoff's Voltage Law:

DC Circuits Review:

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KCL and KVL Circuit Analysis:

Thevenin's Theorem - Circuit Analysis:

Norton's Theorem - Circuit Analysis:

Superposition Theorem:

Maximum Power Transfer:

Physics PDF Worksheets:

[charlestamburelli]

So you know, 6 years later and this video is still a saving grace. Thank you for explaining and breaking things down in a uniform fashion, it is paying dividends in my Circuits class!

[jimtorres]

Went through at least 20 vids on how to do this and your explanations covers it all perfectly and without dead ends, Thank you very much.

[nhlanzekomchunu]

you are just here to make our lives easy. u are such a blessing to us🙌🙌👏👏👏

[petewoodhead]

Thanks for this! I went through it twice with you. First I listened and followed the best I could. Then I took out pencil and paper and worked out every problem trying to stay just ahead of you by pausing your video of course. This was very helpful at driving it in. You made one small error on screen by writing 12v when calculating watts used by R3. I did stumble on this, but finally realized you were saying 24v but writing 12v. Not sure who else caught this, but it actually helped me learn it better, by working a bit harder to figure this out. 😉🤪

[chromerims]

All of your videos are stunningly effective and beautiful. 👍
FWIW at 9:39 forgive me if I am mistaken butI believe that the written 12V should have been 24V. Kindest regards.

[kelindavascodagama]

not everyone explained it well like you. thank you very much . I am glad i found this video .

[tanveerahmad]

thank you so much for not confusing me so much like my instructor!! bless your heart!

[austintittle]

hey man you have helped me so much over the last year, thank you for breaking it down.

[rtbgv]

ERROR ALERT: In the last example at 9:35 you said that you were going to use the forumula P=(V)(I) then you plugged in 12 for voltage and 3 for current but still came up with 72W. I thought I was losing my mind! Otherwise, great video. Thank you.

[wanderingpalace]

thankyou for this gift professor
you made my life much easier and this is beautiful.
Your video is more useful than a textbook with 20+ pages on the topic.

[kristianyoung]

Best channel on yt. Just saved me mid exam.

[EJPCRSKW]

There's an easier way than the reciproca of the sum of the reciprocals. It transforms algebraically to the product divided by the sum: e.g. R1*R2/(R1+R2).

[KirikomiMoon]

I'm sure you get this a lot, but thank you for clearing up the comprehension of circuits! ☺️

[aliciapark]

Thank you so much... I genuinely had no understanding of the circuits before watching your videos. Should have watched them earlier

[johannam.c.requioma]

These videos really help me to answer my modules

[CipherSway]

thank you so much for not confusing me so much like my instructor!! bless your heart! <3

[jalfredl]

At 5:06, there’s also a third way to calculate the total resistance..
R= P/I^2

So, 60 W/5 ^2 A equals 2.4 ohm

[yodad]

Excellent I'm struggling with this even in the learning resources and I've got the BIG closed book exam tomorrow and this is a weak area for me

[daidmwenze]

He's the best, I respect you 🙇‍♂️

[-ghiffaryramadhana]

Woahhh you know everything what a legend