Interesting Exponential Math Olympiad Equation | Math Olympiad Challenge

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Welcome to another exhilarating math adventure in our latest YouTube video: "Interesting Exponential Math Olympiad Equation"!

🔥 Prepare to unravel the mysteries of exponential equations with a captivating problem: 8^y = 80. Join me as we break down this intriguing equation and employ clever math tricks and algebraic techniques to solve it.

🎯 For aspiring math enthusiasts, whether you're preparing for the Thailand Junior Maths Olympiad or aiming to conquer the American Math Olympiad, this problem will challenge and elevate your understanding of exponential mathematics. It's a vital step towards sharpening your skills for competitions like the International Mathematical Olympiad.

💡 In this video, we'll delve into the depths of algebra and problem-solving, revealing the secrets behind cracking complex exponential equations. Understanding these concepts is key to conquering challenging math problems and excelling in prestigious math competitions.

🧩 Ready to dive into this brain-teasing challenge? Hit play and let's explore the fascinating world of exponential math together! Don't forget to hit "Subscribe," like, and share this video to spread the joy of solving challenging math problems. Let's embark on this mathematical journey and unlock the beauty of exponential equations. 🚀 #MathOlympiad #ExponentialEquations #Algebra #MathTricks #MathChallenge
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The most interesting part is outside the camera view. 1:35 I had to look it up. the product rule for logarithms say log (mn) = log n + log m so log 80 = log 8 + log 10.

jollyjoker
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80 = 5*2^4 = 2^(3y)
2^x = 5 implies x = ln5/ln2
Thus, 5*2^4 = 2^( ln5/ln2 + 4) = 2^(3y) implies
3y = 4 + ln5/ln2 or y = (4 + ln5/ln2)/3 = 2.1073...

wes
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I was wondering why a totally routine exponential equation no tricks whatsoever in the solution was called an Olympiad Problem.

attica