implicit differentiation with square roots

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In this math example, we are given an equation that contains two variables, both under square roots. We find the derivative, y' = dy/dx, and evaluate it at a given point by using implicit differentiation. Each step of this process is gone through and explained as we use the power rule to take our derivatives, then rearrange the equation to isolate y' on one side by itself. Because of the square roots, we rewrite them as fractional exponents and use the power rule, that makes us end up with negative exponents. These are rewritten as positive when simplifying.

sqrt(x)+sqrt(y)=
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I can actually see how powerful this implicit differentiation technique is when you apply it to related rates of change

OSAS
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You just simply find a formula that relates all of the values that you’re either trying to differentiate or not, and you simply differentiate that formula and then solve for the differential you are looking for.

OSAS