Uniform Electric Field (2 of 9) Motion of Charged Particles Perpendicular to the Field

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Explains the motion of charged particles as they move perpendicular to an electric field. It shows you how to determine the velocity, acceleration and displacement of the charged particle in the y direction as it moves across the electric field. Also included is one easy to follow worked example.

When two metallic plates are set a distance apart and then are attached to a potential difference, a battery for example, one plate will have a positive charge and the other plate will have a negative charge. The electric field will be directed away from the positive plate and toward the negative plate. The electric field between the plates is uniform throughout. That means the electric field strength is the same everywhere inside the parallel plates. Only at the ends of the plates will it show a non-uniform field. Such a system can be referred to as a parallel-plate capacitor.

Work must be done to move charges from one plate to another. The work can be done on the charged particle either by an external force or by the electric field. The work done on the particle will be equal to the potential energy given to the particle. Using the law of conservation of energy (initial potential energy = final kinetic energy) the velocity of the charged particles can be determined. The acceleration of the charged particle in the electric field can be calculated using newton's second law. Because there is a uniform electric field between the plates, the charged particle will experience uniform acceleration.

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Chapters
00:00 Motion of Charged Particles Perpendicular to the Field
00:45 Explanation
05:07 Worked Example Problem

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I'm studying at university and of all the videos I've covered, THIS... is the most professional and simplest of them all!!

a.robberts
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Professors make this concept much more complicated than it needs to be... thank you

be
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I have been trying to figure out a theoretical variant of this problem for like 6 hours and NOW I FINALLY KNOW HOW TO DO IT! Bless you man!

galaxywanderer
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I am an Indian High School student this Explanation is remarkable. Not many people are able to explain it that perfectly and smoothly. I am very thankful.

hiteshsingh
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I was struggling in physics today with a very similar question. I could not thank you enough for this video! Awesome job :D

mjackson
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These explanations are so clear and simple. Thank you sir, much appreciated!

Anonymous-petk
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The explanation is clear, his workings are good i have to say this is genuine.

epic-simataamushe
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My professor made it over compilicated in his slides
But know it's much easier
I am 1st year Computer Engineering from Egypt and happy I found this video
Keep up the good work

joeLotfy
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Amazing analysis, I have tons of questions related to Earth motion in relation to electron motion and the warbling effect of earth around the sun. This is just a mind blowing phenomenon. I was thinking about the electron speed vector at the right side of the field, and now I can sleep better.

fifaham
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Thank you so much for the detailed explanation! You're a savior :)

laurence-emmanuellebedard
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thank you for your effort, clear and simple

monaelyakoubi
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I'm so glad I found this video, Thank You

mihirbose
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so helpful!! couldn't survive physics II without :)

allieblount
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Your videos are so helpful. Thank you so much.😊

tsoojbaterdene
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Thank you so much! My final is in 5 hours you helped me so much

mary._.
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Sir, is there any condition of charge particle could leave the space between two plate that contains the electric field? Some, case charge particle couldn't leave.

LEUPAGEPLUS
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While everyone is writing they are studying this in am studying this for grade 12 CBSE boards in India 🤦🙇.... Btw, Thankyou for the well versed explanation....I am a subscriber now 😄

prakrutidas
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hey, to calculate the acceleration wouldn't we also have to take into account the effects of gravity? thank you for the video

quasiqidwai
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Very nice and clear. However, you've confused tangent with its inverse in a significant way. The *tangent* of the angle is equal to the ratio of the side lengths given. The inverse tangent is simply used in the *solution* of the equation, to solve for the angle.

ethanbaldinger
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Thank u☺️
U clear my doubt by just diagram 😄

shalininareti