Four charges equal to `-Q` are placed at the four corners fo a square and a charge `q

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Four charges equal to `-Q` are placed at the four corners fo a square and a charge `q` is at its centre, If the system is in equilibrium the value of `q` si
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Pehli bar aisa video mila jo detail me hai ..thanks for this bro..

BabitaKannaujiya-gz
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This is the first video of doubtnut in my life which I could understand problem with all the concepts 😅😅

AdarshRajsahu-sn
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Majduri se h duri...Mr star h jaruri🌟
We know that the net force of a system is zero, so by calculating the option of question.. in whichever option is 0, that will be Answer...

. For direction.. System in equlibrium means..? q present inside the Square is in rest.. Thats q oppose the Q .
and here -Q present at the corner...means.small.q will be..-q.. thats Solve

skdpriyanshu
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Thank you sirrrr..., radhe radheshyam seh miladeee, jai shreeekrishnnn❤

naveenyasoju
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This is my first video on doubtnut which I understand properly 😅😅😅

rtgamer
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-Q, -Q repel each other so how u take the direction from one -Q charge towards the another -Q charge

kusumdhull
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How did it become Q/4 it should be Q/2??

Cricketxlove
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4:06 yaha Q ka -sign kyu kha gaye.

???

gauravmishra
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Can any one please explain how root2 came on resultant

Mushasi_the_legend
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why f3 is positive it should be negative because one is negative and other is positive

Sangeeta_m