Four charges at the corners of square, find net force on one of the charges

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After a year of taking my physics course, and exactly 2 weeks before my FINALS begin, I JUST got it. There is hope yet. Thank you from the BOTTOM OF MY HEART

nihilisticnirvana
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Thank you sir for clearing my doubts. You are great 😃

RohanKewat-vpvk
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Darn, I forgot to break the diagonal vector into it's components! Thanks for the video!

patrickmayer
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Shortcut for you guys

1. as we find the net force on F34 and F14 we see the angle between them is 90°
So we can directly write √2kQ²/r2 and when angle is 60° we can write √3kQ²/r²

Tanuj
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hi sir, this is slightly incorrect. you put the parentheses in the wrong place. they should be around 1/2 and sqrt(2). the way you put them is like we could add .5 to sqrt(2)*kQ^2/L^2 and have the answer but that wouldn't work as we need to multiply both .5 and sqrt(2) to kQ^2/L^2 and add it... so correct answer is (1/2 + sqrt(2))(kQ^2/L^2).

annas
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Sir, why can't we use the vector addition on the resultant of q1, q3 and the electrostatic force by q2??

Vibe_finder
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What is the direction of the net force acting on the charger?

KaizerThoko-xmzb
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Can we take resultant of the diagonal and the firce due to the sides

hmmmm-rj
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One
If Q2 is negative 5 and Q4 is negative 5 what is the force of direction on Q2 due to Q4

AamrithaSR-ngwq
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Thankyou sir awesome explanation but the notations are incorrect for example the force on charge 4 due to 1 is F41 but u write F14 otherwise everything is good 🙏

BholaCoachingCentre
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Is this equation only for this type of question?

angelica-wnxn
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help, where did the other kq^2/l^2 go...

sireneleigh