sec^3 x tan x dx, Evaluate the indefinite integral.

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sec^3 x tan x dx, Evaluate the indefinite integral.
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FOR THOSE WONDERING ABOUT MISSING STEPS


What he did was take one sec(x) factor out so that he was left with sec^2(x)*sec(x)*tan(x). You can see that, with u = sec(x) and du = sec(x)tan(x), the sec(x)tan(x) cancel out so that we are left with sec^2(x) or u^2.

jhansenhlebica
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Just a side tip, people that come on here have no clue what they are doing, and they would love clarification. I just came to check my answer, but hey. But really we need help haha.

mrvomitman
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This worked for me. My school uses webassign...very unforgiving...thx!

PrincessPea
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Great video. This just still doesn't make any sense. How are we able to pick and choose which sec(x) ends up as part of our "u"?

JDMaxton
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El resultado de la integral que se resuelve en el video es incorrecto sumandole que tiene mál procedimiento; el resultado correcto es: 1/3sec^3(x)

yesshc
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how come it's u^2 and not u^3 after you sub u back in?

katiiiielynn
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This has got to be the MOST unhelpful thing i've ever seen

husse