4.10 Assuming that the diodes in the circuits of Fig. P4.10 are ideal, utilize Th ́evenin’s theorem

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4.10 Assuming that the diodes in the circuits of Fig. P4.10
are ideal, utilize Th ́evenin’s theorem to simplify the circuits
and thus find the values of the labeled currents and voltages.
Hwmadeeasy
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For those who are confused about Vth, it's a Source Transformation using the 5V and 10K, changing to a current source and parallel resistor. Then you combine parallel resistors (10||10), then source transform back into voltage source to get the "vth". The circuit diagram notation in this book is very different so it's extremely difficult to see.

AltohP
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The issue is that instrutors are assigning this problem without saying to use Thev, but in the text, this is how Sedra intended for the problem to be solved.

KevlarSammy
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what will be the current through the diode if it has 0.7V drop

shufflex
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Can solve questions using other diode models plz..

nl
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What can we do diode cut in voltage is 0.7v. is also method? In forward baise diode we assume short circuit like above problem

allurusrinivasulu
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did you use KVL to get v=1.5V-2.5V ignoring the resistor since current doesn't flow through it?

austinmendoza
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sorry but how and where did you get the 5k ohm resistor from I don't understand

fluffyzozo
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...one must emphasize the ideal diodes in this case act as a switch, requiring 0 bias voltage: a switch which opened has infinite resistance and which closed has zero resistance.

lorigianow
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From which book are the problems taken?

tanjim
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voltage divider equation is vin * (r1/r1+r2). Source is 5v not 10 and 5v is not a resistor. thus numerator of you voltage divider 2:04 is wrong

michaelcedeno
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why you say 10k & 10k are in parallel aren't they in series?

meenakshitomar-ks