20c - 🔴MIDSEM EXAMS: Norton's Theorem Problems #knust

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20c - MIDSEM EXAMS: Norton's Theorem Problems #knust

In this video we are going to learn how to solve circuit problems using Norton's theorem.
Norton's theorem states that any linear circuit connected between two terminals can be replaced by a Norton's current IN in parallel with a Norton's resistance RN.
To find the current flowing in a resistor;
1. Remove the resistor you want to find the current through and mark the terminal
2. Find the IN using KVL
3. Deactivate all independent sources, open circuit current sources and short circuit voltage sources and find the RN
4. Produce the Norton's equivalent circuit and reconnect the resistor you removed.
5. Find the current through the resistor using the formula I = RN/(RN + RL) * IN

00:00 - Problem 1
10:01 - Problem 2

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Thanks for the help. Very few examples out there with more than two sources. I needed this.

jdanderson
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For the second calculation, why are we adding the 20 Ohm to RT ', because current takes the easy route, so there wont be current flowing in 20 ohm, since its connected parallel to IN' ?

siphesihlenkosi
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Thanks for the good work🙏.
Request: Could you make a video on Millman's Theorem.

winter.k.mwanza
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Please record a video on Reciprocity Theorem

MemorizeQuranEasy
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Also, now that I have a Norton equivalent of my multi-source project, I would like to see what the Thevenin equivalent is. If you were to explain it as well as you did here, it would build my confidence.

jdanderson
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Sir you not add super position theorem in problem 1 and add super position theorem in problem 2, how wo detect in which problem we add super position theorem??? Kindly clear me please 🙏

fakhir_
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Please I have a
In example 1, why did you choose 2 and 6 to be in series over 8 and 6 when solving for the Norton's Resistance?

emmanuelboatengjunior
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the second example what if the sources are more that 2 like 4 can i still use the superposition

khalid
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Good work but try explaining some parts in detail, , Kindly🙏🙏🙏

BrianKipturu-yckh
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Sir, why did you say I1 = positive 0.75 instead of -0.75, as it is moving in the oppositive direction.

yodelndimande
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Sir please why didn't you use the last loop to find I1 .

DesmondAnsah-vtgf
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Hi sir if i solve norton's theorem exactly how you taught us how to solve thevenin i'm still correct right i mean in terms of finding vth?? i don't know if you get my question.

mohubemahlatsephaladi
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You could have used the current duvision rule to find the I1

DanielBoateng-ju
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I don’t know if my method of approach is okay, but I used;

In = 3 + I (kcl)

Using kvl; first loop

25 = 5*I + 20*I
Solving this should result to 1

From kcl,
In= 3+1 = 4

addetnancy
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Why didn’t you take the last loop but the second one on the first example

paiterhammondkodua
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On problem number 1 how to get the load resistance (Rl) pls answer my question thank you:(

Olakk
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Geez Louis, use source transform dude. Your method is like the second most tedious method next to node and mesh analysis.

excalibirb
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pleae can you just use the norton theorem procedure alone without SUPERPOSITION

NANOR_OB
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boylsted or sadiku
Which one is good

xavier
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Sir in problem 2, according to problem 1 if the current direction is downward 👇 we take it negative but in problem 2 both currents IN'and InN" is downward 👇 but you take it positive why sir ?

fakhir_
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