College Algebra/High School Mixture Word Problem

Try these on your own...

The manager of a store that specializes in selling exotic tea decides to experiment with a new blend. She will mix some Jasmine tea that sells for $9 per pound with some Hibiscus tea that sells for $3 per pound to get 100 pounds of the new blend. The selling price of the new blend is to be $5, and there is to be no difference in revenue from selling the new blend versus selling the other types. How many pounds of the Jasmine tea and how many pounds of Hibiscus tea are required?
Ans: Jasmine: 33.33 lbs, and Hibiscus: 66.667 lbs.

The manager of a store that specializes in selling exotic tea decides to experiment with a new blend. She will mix some Jasmine tea that sells for $10 per pound with some Hibiscus tea that sells for $4 per pound to get 120 pounds of the new blend. The selling price of the new blend is to be $6, and there is to be no difference in revenue from selling the new blend versus selling the other types. How many pounds of the Jasmine tea and how many pounds of Hibiscus tea are required?
Ans: Jasmine: 40 lbs, and Hibiscus: 80 lbs

[billy.]

This one is similar to the bike problem. "Bicycles and tricycles are 40 in all. There are a total of 93 wheels. How many bicycles? How many tricycles?"I had been taught to solve these word problems when I was 10 in China many decades ago. No algebra needed. With deep understanding, all you need are some very basic arithmetic. The old Chinese math followed the Soviet math education model. I am not sure what is going on in Russia now. But the Chinese march on and stronger than ever.