Vectors & 3-D Geometry Problem Solving | Class 12 Maths | CBSE 2024 | Shimon Sir

𝐓𝐚𝐦𝐢𝐥 𝐍𝐚𝐝𝐮 𝐒𝐮𝐩𝐞𝐫𝐬𝐭𝐚𝐫𝐬 𝐂𝐞𝐫𝐞𝐦𝐨𝐧𝐲 𝐑𝐞𝐠𝐢𝐬𝐭𝐫𝐚𝐭𝐢𝐨𝐧 𝐟𝐨𝐫 𝟏𝟎𝐭𝐡 & 𝟏𝟐𝐭𝐡 𝐩𝐚𝐬𝐬 𝐬𝐭𝐮𝐝𝐞𝐧𝐭𝐬

Elevate your Class 12 Maths skills with this comprehensive session on Vectors & 3-D Geometry problem-solving, tailored for CBSE 2024 curriculum. Join the brilliant educator, Shimon Sir, as he simplifies complex concepts, providing step-by-step solutions and practical insights.

🔍 Topics Covered:
📌 Introduction to Vectors
📌 Vector Operations and Properties
📌 3-Dimensional Geometry Basics
📌 Vector and Scalar Triple Products
📌 Application of Vectors in Problem Solving
📌 Real-world Applications and Examples

🚀 Boost your understanding of vectors and 3-D geometry, and gain a competitive edge in your CBSE 2024 exams. Shimon Sir's teaching methodology ensures clarity and mastery of these crucial topics.

𝐃𝐢𝐬𝐜𝐨𝐯𝐞𝐫 𝐎𝐮𝐫 𝐃𝐢𝐯𝐞𝐫𝐬𝐞 𝐏𝐥𝐚𝐲𝐥𝐢𝐬𝐭𝐬 𝐃𝐞𝐬𝐢𝐠𝐧𝐞𝐝 𝐓𝐨 𝐌𝐞𝐞𝐭 𝐘𝐨𝐮𝐫 𝐒𝐩𝐞𝐜𝐢𝐟𝐢𝐜 𝐋𝐞𝐚𝐫𝐧𝐢𝐧𝐠 𝐍𝐞𝐞𝐝𝐬:

Our channel is your ultimate resource to achieve top scores in your academics. Join us as we navigate through CBSE Board Exams 2024 and beyond! 🎓

🔔𝐒𝐮𝐛𝐬𝐜𝐫𝐢𝐛𝐞 𝐭𝐨 𝐎𝐮𝐫 𝐎𝐭𝐡𝐞𝐫 𝐜𝐡𝐚𝐧𝐧𝐞𝐥𝐬🔔

Stay tuned for strategy and motivation, sample paper solving, shot marathons, revision techniques during exams, and career guidance. Meet your favourite teacher, Shimon Joseph Sir, an IT Madras graduate and a KVPY Scholar (JEE Main Tamil Nadu State Rank 5).

❤️𝑹𝒆𝒎𝒆𝒎𝒃𝒆𝒓, 𝒚𝒐𝒖𝒓 𝒔𝒖𝒄𝒄𝒆𝒔𝒔 𝒊𝒔 𝒐𝒖𝒓 𝒕𝒐𝒑 𝒑𝒓𝒊𝒐𝒓𝒊𝒕𝒚!
🛒 𝑾𝑬 𝑯𝑨𝑽𝑬 𝑳𝑨𝑼𝑵𝑪𝑯𝑬𝑫 𝑶𝑼𝑹 𝑶𝑾𝑵 𝑺𝑻𝑶𝑹𝑬! 🛒


🌟 Start your learning journey with Vedantu Master Tamil today, and let's achieve academic excellence together! 🌟

#Class12Maths #MathProblemSolving #Vectors #3DGeometry #vedantumastertamil #cbse2024 #neet2024 #jee2024 #cbse #boardexams #ncert2024 #ncert #class10 #class11 #class12 #shimonsir

[katie_]

Yaarukulam relations and functions chapter vennumo like podunga namba req pannalam sir kitta

[YazhiniAnbuselvan]

foot of perpendicular is (1, 6, 0)
length is root( 24 units )
image point is (-3, 8, -2)

[poojasundhari]

26:49 He actually told the mind of Gethu batch ✅

[nithishm-kurt]

homework question answer is lamda =1 and foot is (1, 6, 0) and image is (-3, 8, -2) and length is root 24
and equation of line is 2x+4y-26=0

[anifan-zdcz]

SIR ANSWER FOR THE LAST QUESTION IS
PERPENDICULAR POINT = (1, 6, 0)
IMAGE POINT = (-3, 8, -2)

[darkprince]

HW Question Answer
Lamda = 1
Foot of the perpendicular (1, 6, 0)
Image of p (-3, 8, -2)
Length=√24
AD^2🔥

[NithinK-ykzz]

sir answer for the last sum foot=(1, 6, 0) image=(-3, 8, -2) length=root 24 units

[sadgaming]

2:22:40
Sir your explanation for foot of perpendicular was awesome...it looked very easy to understand... Thank You

[Thehorrortimes]

1 subscribe = 95% In board exam
Ignore ka risk matlo😢😢😮😮

[mohamednumair.m]

Coordinates of foot of perpendicular is (1, 6, 0)
Length of foot of perpendicular is 2root6 units and the image of p in the line is (-3, 8, -2) sir

[toptuckerinformations]

sir answer for
foot of perpendicular is (1, 6, 0) Lamda=1
Length of perpendicular 2root6 or root24
Image (-3, 8, -2)

[sumathras]

Sir plss applications of derivatives ku live podunga sirrr

[sharmilakaruppaiyan]

realtion and function and inverse trignometry sir video sir

[m.rakeshroshan]

Good Evening Sir,
Foot of perpendicular from point P is (1, 6, 0)
Image of point P is (-3, 6, -2)
Length of perpendicular from point to the line is 2 _/ 6 units sir.

[mahesmonica]

Sir tomorrow probablity needed sir..❤️

[yugapooja]

Sir application of integrals sir please

[saureshtheking]

Sir jee mains maths ku video podunga sir useful ha irukum 5:12 5:15

[senthilkumarparamanandan]

foot pt(1, 6, 0)
mirror img pt(-3, 8, -2)
length of perpendicular=2 root6

[sadhanapriya]

my answer
lamda=1
ft of perpendicular:(1, 6, 0)
image:(-3, 8, -2)
length of ppr:root 24

[infantpatrick]

Sir answer id
Foot point=(1, 6, 0) and
Image point=(-3, 8, -2)