15.2 Le Chatelier's Principle | General Chemistry

Chad provides a comprehensive lesson on Le Chatelier's Principle which states that if a stress is placed on a system at equilibrium, the system will respond to counteract the stress. If you're at all struggling with this concept, then check out this lesson as Chad explains Le Chatelier's Principle from 3 different perspectives: based upon the definition, by comparing the reaction quotient (Q) to the equilibrium constant (K), and by comparing the forward rate to the reverse rate. They all reinforce each other to help the student correctly predict whether a system will shift left or shift right including how to predict temperature and pressure effects.

00:00 Lesson Introduction
00:28 Introduction to Le Chatelier's Principle
01:10 The Reactions Quotient and Comparing Q to K
06:14 Adding a Reactant (Shift Right)
09:21 Removing a Product (Shift Right)
12:15 Adding a Solid (No Shift)
13:41 Changing the Temperature
17:52 Changing the Pressure
21:24 Adding an Inert Gas

[beagonzales]

HOW IS CHAD NOT MONETIZED??? He's literally the best! I've been having a hard time understanding what happens if the pressure is changed and this is the only video that helped me. Binging his other videos!

[mambo]

i just want to let you know that youre helping out people (like me just now) with your videos to this day

[itsdhrubo]

It is hard to get such quality lectures on YouTube. Very well explained and hope you will keep up the good work...

[toolsstop]

I feel like a criminal watching these lectures for free. Absolutely stunning work Dr. Chad

[ashleem]

I am so thankful I found your videos! You are a great teacher, and I wish I had found you in gen chem 1! I love that you take the time to teach each aspect of the section. My professor teaches quickly and skips many small steps, so your videos help me actually learn the material.

[ConnorStear]

I had to stop and applaud how beautifully simple you made everything right around the range of 3:40 to 4:40. Everything clicked so well it's like I could feel the neurons firing in my brain lol.

[lifefjah]

youre the best man, you explain things so well! THANK YOU!

[SakeenaManzoor-uy]

Sir l know you are the only teacher who can clear away my all confusions relevant to my questions😢

[saqibkhan]

Chad, In the last lecture you said that only temperature can change the equilibrium constant. So it is fair to say that when we are are changing the concentration of reactants and products, we are not changing the equilibrium constant but rather the reaction quotient. So when we change the reaction quotient, this shifts the reaction in a way that allows us to get back to the equilibrium constant which remains the same value because only temperature can change the equilibrium constant? (I hope this makes sense).

[kimberlysanchez]

Thank you so much!!!! Been watching all of your chem videos <3

[devikanair]

thank you so much for explaining the effects with temperature. I was struggling with that for a long time b/c I was confused how shifting T changes a rxn b/c it affects equilibrium. One quick question! how would you reconcile that delta G = -RTlnK but if you added heat in an exothermic reaction the delta G should be less negative, but according to the formula if you increase temperature the Delta G would be more negative? loving the new playlist!!

[GeorgeCronigen]

Really good video mate thank you a lot. Just a question if you can answer with a yes or no. We said that we must know if a reaction is endothermic or exothermic in order to know if heat will be on the products side or on the reactants side. But this alone isn't enough to determine wether the reaction will shift to the left or right. We must also know if we are increasing or decreasing temperature because this tell us if we are adding or not heat to the already existing heat which is enlisted either in the products or the reactants. In other words we need to know if heat as product or reactant is increasing or decreasing. Thank you a lot for all your help.

[captainamericawhyso]

AMAZING VIDEO ONCE AGAIN ! Just a question though when i add argon won't the collisions between the reactants become fewer? Before, in the same volume there were only these two reactants: solid carbon and diatomic gas oxygen. But now that we added the argon some of the collisions are going to be with the argon rather than between the reactants. So if its harder for the reactants to collide with each other shouldn't the reaction sift to the left ?

[ذَكاءذكاء-ذز]

All three changes: 1- Withdrawing or adding to the interaction
2-Change the volume or pressure
3- Changing the reaction temperature
It will change with the concentrations of substances for the equilibrium reaction
Why is it only temperature that changes the value of the equilibrium constant?

[destinycross]

Hi, you said shifting to the right causes the Q value to go up, I thought it causes it to go down since it Q<k

[SakeenaManzoor-uy]

Dear sir you asked that change in conc of either reactants or products at eq doesn't affect the value of Kc but if we increase the conc of O2 here the reaction will go in forward direction and reverse reaction remains unchanged and after a second the consumption of extra O2 again rate of forward reaction also becomes slow down and both rates again become equal . In other hand if at eq we decrease the conc of Co the reaction will go in forward direction but in this case we have no extra addition of reactants or products but our normally present reactants at eq are consuming and in this case the rate of reverse reaction slow down and after a second both the rates again become equal sir how both these reactions could have equal value of Kc😢😢😢😢

[saqibkhan]

Another Question, What if we decrease the pressure by increasing the volume? How would this effect the shift of the rxn?

[ذَكاءذكاء-ذز]

Do pressure and volume affect the equilibrium constant? If they don't affect it, how?
I got confused about it
Especially when I was watching the clip at minute 19

[destinycross]

why would we shift Co to right and not left to decrease Co?

[shamsalnaharrajoub]

Why adding solid will not affect equilibrium position? Adding solid will produce more products