Efficiency Of A Rankine Cycle | Professional Engineer

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This clip is from HVAC & Refrigeration Office Hours for the PE Exam with Dan Molloy, PE. I'm not going to do this problem out fully i want to challenge and invite the person who asked this question to kind of double down on attacking the table and the reason for that is it's so important to be able to find the information you need in the reference handbook quickly and reliably and you have to be patient with yourself
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You are correct that the enthalpy added by the pump is very small and has little effect on the efficiency, but you do have enough information to calculate it. The work done on the system by the pump is the specific volume of the fluid at state 1 multiplied by the difference in pressure between states 1 and 2. The specific volume at state 1 is 0.0162 ft^3/lbm. This gives the pump work as v1(p2-p1)(144 in^2/ft^2)(Btu/778 ft-lb) which equals 2.09 Btu/lbm. Add the pump work (enthalpy change) to the enthalpy at state 1 and you have the enthalpy at state 2. This gives 2.09+94.01=96.1 Btu/lb. The efficiency calculated this way is 38.97%. If the pump work is negligible the efficiency is 39.06%.

NineteenHand
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Consider isentropic efficiency as 100% for both pump and turbine, the thermal efficiency will be 39%.

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