A TRICKY PATHFINDER MODIFIED CHALLENGE IN ELECTROSTATICS--CHECK YOUR SCALING TECHNIQUE SKILLS

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Q: If potential and are given , find ?

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Why only 80 likes and 1 k views???😨😨😰... atleast u all can like the video if you are not sharing thinking that competition will increase 🙏😑😑

divyanshukumar
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Learned a new method today. Thanks a lot sir

arpitbansal
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The concept of scaling could be used in such problems! Grateful enough for bringing up this concept thank you sir 🙌🙌

simisimi
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Shouldn't we scale up or down using sin square and cos square because that accounts for the amount of charge. For that area

pranavprabhu
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I first calc Vc=Vacosø+Vbsinø and then Vd=Vc(cos+sin)

amiyancandol
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thoroughly enjoyed the problem and your unique solution sir, thankyou for sharing this

rmishra
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Opp! I am enjoying watching your videos ✨

maths
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Learned a new thing today.
Concept clear sir🙏🙏😎

grandson_f_phixis
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Never thought symmetry would make such problems very simple!!

aaryansahu
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Excellent explanation of given question

surendrakumarjakhar
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sir is there any logic behind the dependency of potential on theta? In other words, why did we introduce the 'f(theta)' function?

ali
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Sir why does Potential at the vertex having 90 deg not have a shape factor dependent on theta? Im not able to find why

chandrashekariyer
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Sir at 8:34 I think we cannot replace the f(90-theta) with Vb/c as charge is also changing the charge in smaller triangle is less than initial one
Sir I attempted the problem by writing different charges as the arrangement is same
If initial charge was Q then In smaller triangle it is coming Qcos^2 theta
But ended up getting wrong answer sir please clarify 🙏

Raj-igwi
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Superb Explanation Sir.
I would like to ask that would this dimensional analysis method always work ?

Sachi_Ray