Proof of Inclusion-exclusion Principle. Part 1

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Please watch: "Real Projective Space, n=1"
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Thanks brother, your video helped me a lot.

chiranjitbora
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Correct me if I'm wrong. If *n* (or *k* ) were *0*, then the set would be the empty set, so *A* and *B* couldn't be disjointed, since one of them would be a subset of the other one.
Edit: I just realised: if the definition of "disjointed" is that *A∩B=ø*, then they would be disjointed... Because *ø∩B=ø*, isn't it? But *ø* is a subset of *B*
So, are they or aren't they disjointed?

andresxj