Physics 37.1 Gauss's Law Understood (28 of 29) Infinite Cylinder of Charge 3

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In this video I will find the electric field E=? a distance from an infinite cylinder (cylinder is a INSULATOR, charges evenly distributed inside) of charge where the VOLUME charge density is given.

Next video in this series can be seen at:
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thank u so much professor after hours of reading and studying my course's material I couldn't understand a thing about gauss's law and how I use it so therefore I thank u for this playlist I now know how to approach these problems !!!

MRL
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I am here trying to apply this to the multi variable version of the problem using Cylindrical coordinates and integrating a function of rho to obtain charge in-enclosed... life is great LOL. Oh how I wish I did better in my electricity and magnetism class that didn’t require clac 4 and was much easier then the E and M I am doing now 😫

fuge
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Thanks for greasing my brain . Preparing for jee advanced, wish me luck professor

ArthBachhuka
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For E outside shouldnt the answer be E=(pa)/(2Eo)? Because, wouldnt we use the area of the actual cylinder and not the gaussian area if we wanted the E outside of the cylinder? I understand the E inside completely, thank you for all the help and for the extra help in advance!

jadrun
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I was looking for this, thank you for this video ^^

elifnazlibey
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Sir (talking about the case of finding electric field inside solid cylinder )here there are charges inside and outside our assumed gaussian surface so wont charge outside and inside of our gaussian surface repel each other thereby creating a null point on our assumed gaussian surface ?

saiyamjain
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Hello, is there a particular reason that we cannot just keep the Qin for the gaussian surface when R>a to be Qin? I do not see how for the insulating sphere (when R>a) the Qin stays the same, yet for this example, Qin is substituted with (rho)(V). I referred to your video on a sphere with uniform charge but I don't understand why the Qin changes for the cylinder but not for the sphere when both have R>a.

jinxed
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What happens if there is a hole inside the cylinder

rzagunes
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how come for the last video the qin = 2(pi)(a)(L) where a was the radius of the cylinder and in this video the charge density = pi(R)^2 (L) where R is the radius of the gaussian cylinder not the infinite charge cylinder?

cortiz
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Does charge enclosed by the gaussian surface depend on the length of the gaussian surface?

boboganbobogan
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Guys does the Electric field will become zero if you increase the radius of the gaussian surface?

netzkeiescobal
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doctor R is not same then you can't cancel it ?!

dyhaal-basha
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can we take another gaussian surface like sphere or a disc?

dffvzzg