Uncertainty - Multiplication and Division

This video tutorial discusses how to multiply and divide numbers with uncertainty values.

Uncertainty - Addition & Subtraction:

Uncertainty - Multiplication & Division:

Uncertainty - Powers & Roots:

Averages & Uncertainty:

Accuracy and Precision:

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Significant Figures - A Fast Review:

Scientific Notation - A Fast Review:

Unit Conversion Mega Review:

Student Loan Calculation:

How To Save Money & Time In College:

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General Chemistry - For Beginners:

Organic Chemistry - Basic Introduction:

Physics - Basic Introduction:

Algebra For Beginners:

Excel Tutorial For Beginners:

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SAT Math Part 1:

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Full-Length Videos and Worksheets:

[centerofgameplay]

I have past up from 9-12th grade from watching your math videos, and I've gotten complements from how much I have learned, and from how fast. thank you for what you do man, your making a real difference in the world!

[lemeschin]

I don't know about you guys, but I absorb more from this channel more than me in my classroom,
-Your videos are great bro very helpful

[wjtk]

Man, you help me so much. I am so grateful!!!

[jayceel]

you are the actual best, please keep on making physics videos

[jjcadman]

Generally, the last significant digit indicates that you know that value within +/- half of itself (so, if you had a ruler with only inch markings, you could estimate something to within the nearest inch, because the best you could do is guess whether it was more or less than halfway to the next inch; if the ruler had 0.1 inch markings, you could easily determine how many tenths of an inch it had towards the next inch, but then you'd have to estimate whether it was more or less than halfway between two consecutive tenths of an inch).

It seems unusual that you could have a value to 0.1 cm as the last significant digit, and not be estimating it +/- .05 cm.

But, (using the examples from the end of the video, since the frame is paused on my screen) I suppose if your measuring system were actually at 1.2 cm intervals (0, 1.2, 2.4, 3.6), then you would have to report your measurement as one of those values +/- 0.6 cm. So, while somewhat unusual, one could report results to a significant digits place that is the same as the uncertainty measurement's place.

[EclipseAssassin]

Thanks sir, I have learner a lot from you.

[esterotto]

Thank you this helped me I was indeed struggling

[maxwellkreizinger]

Wouldn't it be more accurate to add the errors in quadrature or am I mistaking that with propagation of errors?

[konlion]

what if you multiple AND divide in the same equation

[dugowlw]

Shouldn't the centimeters be squared in the first example?

[nickpatella]

I don't really get the point of sigfigs when using these error intervals, other than brevity, but that's just rounding then, nothing to do with significance

[TadalaJiya-lyui]

Is it necessary to multiply with a hundred?

[galaxyas]

Why do you HAVE to round the results? Seems like you are deliberately decreasing precision.

[Jackadman]

this doesn't really make sense especially when it's ignoring the propagation of uncertainties, am I missing something?

[melissafaiyth]

I'm so going to pass my exams now 🥰

[tomkotch]

The division problem should be unitless

[jorgelima]

Multiplying N cm x M cm should result in NxM cm2 (centimeter squared) not NxM cm !!!

[tco]

This is so wrong.. Where is the formula you are suppose to use? the e = square root of e1^2 + e2^2?

[Last_smile_forever]

Addition of Percentage is Wrong 👎 !! Correct is 4.8440%

[livisimon]

He got a pitching voice, this bores me