Electric Field Due to an Infinite Sheet of Charge and Parallel Plate Capacitor

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Physics Ninja looks at the application of Gauss's Law to find the magnitude of the electric field produced by an infinite sheet of charge.
  1. Physics Ninja
  2. Physics
  3. Ninja
  4. Gauss's Law
  5. Infinite Sheet
  6. Charge
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This is great video! Clear all of my blur concept! Thank you❤

ufjhbzj
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Doesnt the electric field due to a line charge depend on the distance from the line? Seems like the answer should depend on the height above the sheet.

inGuy
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Thank you so much for your explanation. It is very clear, however, which I don't understand in the second example (two oppositely charged plate): The total electric field is E1 + E2, with E=sigma/2Eo. BUT isnt sigma of the second electric field negative and so if we did the sum of them, it would equal to zero ?
I hope I make myself clear.. I see that we only make the sum of the magnitude.. but I don't understand why we don't respect the polarity of the charge density.
Any help would be greatly appreciated :) thank you so much!

lrssmr
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Sir why whole charge on the sheet is not included in cylindrical gaussian figure just a part of sheet, the formula is (total charge enclosed/epsilon)

Radon.........