An Euler Experience - A dope Integral :v [ ln(x)/(x^2+1) from 0 to infinity ]

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"Is nothing but" *writes 10 pages of integrals*

lukamitrovic
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If an integral doesnt end up equalling a factor of pi or e, get it out of my face.

TheReptileDragons
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The integral from 1 to infinity (so minus the integral from 0 to 1) of ln(x)/(1+x^2) is called the Catalan's constant. It pops up in various "hard" integrals problems. If you want to read more about it, I recommend the article from MathWorld Wolfram about the Catalan's constant.

PackSciences
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I used x = tan(u). Then you get integral from 0 to pi/2 of ln(tanu). Then use t = π/2 - u to get 0 to π/2 of -ln(tant), so the integral is 0.

EssentialsOfMath
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Just substitute x=exp(y) and get an Integral of an antisymmetric function over a symmetric interval -> trivial.

leonardromano
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The Integral Bois are back
Thank you Papa
We love it RAW

The_Professor_S_
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Wow, I absolutely loved this!!! Thank you!!! I learned several new tricks we have yet to see in Calc2!! :-D Danke!

StreuB
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I did it at my classes using complex analysis.
Using that integral(x^α/(x²+1)) from 0 to inf is equal to π/(2cos(πα/2)) [obtained with the Residue's Theorem].
We then do d[integral(x^α/(x²+1))]/dα [from 0 to inf], the differencial enters inside the integral (uniform convergence) and after deriving in both sides we get integral(x^α [from 0 to inf].
Then we make α→0 and we've got our integral :D, integral(ln(x)/(x²+1))=0 (from 0 to inf).
Hope you like this way too.

cadec
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Dope. You have truly stumped me, flammy boi. Bring out the next video, Imma solve that one!

pranayvenkatesh
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"this is just a dummy variable, you can call it your mother or this chair I'm seeing"

liked, commented, subscribed, etc.

Joshwism
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Wow that dog understands -nazi- German, very epic.

Riiisuu
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Had this integral in my calculus 2 final exam 😁

amih
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Only one notes to integral - integral=0. We must be sure, that this integral is not infinity. For example (N) (L) integrals from x , where x is from - infinitiy till infinity don't exist

tgx
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Ah, so this one is the integral that gives the probability of me getting a girlfriend. :/

pi
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this is so cool ! big thanks for that !!

ttnfranch
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I solved the integral of dx/(1+x^2) using partial fractions. I know it's arctan, but I wanted to try to make it fun. I factored 1+x^2 into (1-xi)(1+xi) and did the normal partial fractions and got an answer. It turns out to be the complex definition of arctan:[ 1/2i * ln|(i-x)/(i+x)| ]. You should def try it because it's neat, and over complicating a simple problem lol

crosisbh
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Now this is some Quantum Information & Computation content bois.

avananana
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integrate {log(1+x)}/(1+x^2)
for lower limit= e and
upper limit = e^2

MrMJS-kscc
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I feel the maths I did (probably not that well!) from over thirty years ago, start to make links again in my aging brain. Thank you.

sidstam
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Nothing better than spicy boy and afrojack t shirt!

sebastiian