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[krishgarg]

a = (True, True, True)
a is a tuple with 3 true values
In python, whenever you write anything with commas, it converts it into a tuple
now, "a == True, True, True" is in of itself a tuple, with its 0th element being "a == True", and 1st and 2nd being "True" each.
that's why the 0th element evaluated to false (as a != True but it is equal to a tuple as mentioned above) and rest of the values remained the same.
Thats why we get (False, True, True) at the end.
Bonus: And if you run "a == (True, True, True)" with the brackets, it would just return True, which is expected in the first case.

[gamingvector]

it is like this
first statement : a = ( True, True, True )
Second Statement : ( a == True ), True, True

[ansh_aditya]

Eagerly waiting for your javascript course 🔥🔥

[nivealokhande]

a = (True, True, True)
a is a tuple with 3 true values
In python, whenever you write anything with commas, it converts it into a tuple
now, "a == True, True, True" is in of itself a tuple, with its 0th element being "a == True", and 1st and 2nd being "True" each.
that's why the 0th element evaluated to false (as a != True but it is equal to a tuple as mentioned above) and rest of the values remained the same.
That's why we get (False, True, True) at the end.
Bonus: And if you run "a == (True, True, True)" with the brackets, it would just return True, which is expected in the first case.

[thegreatprogrammer]

in the condition
a == True, True, True
It is comparing True as a boolean with tuple a, hence False. Other 2 Trues are booleans and different 2 different conditions.
The other 2 Trues are like saying
while True:
or if True:
That is, not checking for a particular condition. Just putting True.

So, it is not comparing a with True, True, True tuple.
We r in python repl. So if we type any value, whether boolean or tuple or list, it will be printed.
So a == True, True, True
Is a new tuple of values False, True, True. False is evaluated, other two put as it is.
To compare we need to write
a==(True, True, True)

[karthikeyan]

Here goes like this
First statement : a = ( True, True, True )
Second Statement : ( a == True ), True, True

Comparing These Two results in the output given

[devkaranjoshi]

because it is checking a tuple with only a integer
like
a =(True, True, True)

but it is second statement
a==True, True, True
it is comparing a tuple only with first value
like ((True, True, True)==True) True True
so thats why it is showing result as (False, True, True)

[PrinceRapper]

Operator precedence. You're actually checking equality between (True, True, True) and True in your second code snippet, and then building a tuple with that result as the first item.

Recall that in Python by specifying a comma-separated "list" of items without any brackets, it returns a tuple:

>>> a = True, True, True
>>> print(type(a))
<class 'tuple'>
>>> print(a)
(True, True, True)
Code snippet 2 is no exception here. You're attempting to build a tuple using the same syntax, it just so happens that the first element is (True, True, True) == True, the second element is True, and the third element is True.

So code snippet 2 is equivalent to:

(((True, True, True) == True), True, True)

And since (True, True, True) == True is False (you're comparing a tuple of three objects to a boolean here), the first element becomes False.

[jatingupta]

It is because a is tuple, and a==True condition gives False result and False, True, True returns, which is also a tuple.

[journeyofaa]

In first statement we are giving value to variable :
a = true, true, true
and in second statement we are comparing variable : a == true, true, true

[dipeshsamrawat]

First comma separated value is treated as first element of the tuple, so "a == True" and next two Trues are three elements of the tuple and a new tuple is being generated. And a == True should be evaluated as False so finally (False, True, True) was generated.

Harry Bhai 🤗

[SahilSharma-myyg]

Bcoz
a==true, is condition which is false hence print false
Remains are simply printed as a tuples

[kanishkkumar]

As in first statement

You are declaring variable a = True, True, True
Where as in second value you are comparing value by its variable datatype

[LiveRosemat]

may be this happened because in first code you wrote a=true which means the variable a have a string true but in second code you wrote a== true which means the value of a and true is same its not because a is not defined.

[VaibhavShete]

Comma separated values type karo to woh Tuple ban jata hai. Pehle (True, True, True) ek Tuple ban gaya aur variable a ko assign hua. Baad mein ek naya Tuple ban raha hai, jismein pehla value hai a==True ka evaluation. But a=(True, True, True). So a==True evaluates to False. This is added as the first value of the new Tuple being created. The remaining values come as they are given, i.e., if we type
a==True, 5, 4, True
then this will be printed:
(False, 5, 4, True)

but if we type
a=(True, True, True)
then it will print just:
True

[nilesh]

Ek dam solid hero lag rahe ho Harry bhai lerning ke sath entertainment bhi ho raha hai 🤟

[satyamkarn]

You cannot compare with more than one values at a time and secondly it's a tuple so you have to give the index with it to compare with a particular value otherwise it will return false.

[puspendumaji]

1st case= true word store in a and print value of a and others true just print.
2nd case= now == sign use as a operator. Now that's why 1st is print is false and others normal print true

[baxsm]

1) >>> a = True, True, True -> tuple of "a" i.e. (True, True, True)
2) >>> a == True, True, True -> returns tuple ( False, True, True)

the first value is false (in 2nd) because we are comparing tuple of "a" i.e. (True, True, True) to a boolean True i.e. a == True

[Rahulraj-vukq]

Sencond statement: a==True, True, True
The first true is compared with a and the rest of the True are printed so it show False at first and the second and third True