Adding Consecutive Numbers Math Riddle | Algebra Puzzle Math Hack #shorts #math #algebra #maths

[arpitgupta]

Arithmetic progression
Sn = n/2(a +an)

[mildlyobesegoat]

I figured it out in a few seconds. I‘m proud of myself

[NeverEverClever]

In the 18th century, when the German mathematician Carl Friedrich Gauss was only 9 years old, his teacher in school wanted to keep them occupied for a while so he told the class to add up all numbers from 1 to 100 as an excercise. Gauss solved it basically this way in a minute. He found the formula n*(n+1)/2 to solve these kind of problems in general. The formula is now named after him in Germany.
Edit: Math is hard

[oojkqwi]

Brother you can use Arithmetic progression 's Sn = n/2(a+l) formula
Where,
a = first term
l = last term
n = no.of terms
Sn = Sum of nth terms 😊

[sarkram]

Dude for series addition there is formula. N(N+1)/2

[sethstuff]

Was trying to figure out a way more complicated method that involved finding pairs that add up to 200 and taking adding n/2 (200/2) to it, i think this method could still work but yours is easier to wrap the mind around. Good example!

[outsideconfidence]

I just used the arithmetic sequence formula and that's

[dr.carbon]

🇮🇳 Indian JEE aspirants be like - Answered in a millisecond

[theoverseer]

I was just looking for the median, not sure how it’d go, but if it’s 5, the median number is 3, not 2.5. (Not sure if the terminology works)

200 times 100.5 = B

For 199, its by 100x, for 201, it’s 101x.

[jfkdn]

I’m at uni right now but these videos make me wanna do math voluntarily

[itsmevanquisher]

Simple Arithmetic Progression based question
Sum of n terms is given by:
S(n)=n/2*(a+l).
where a is the first term and l is the last term
and n is the number of terms

[pranay]

Or you can just use Arithmetic Progression formula

[nycuba]

You can also do (n × (n+1))/2
Where n is the biggest number in the sequence

[Looop-qvoq]

Gauss be like: MAN! Just use the formula and have 200x201 all divided by 2, simplifiy the 2 with 200 and get 20100

[senseigaming]

Just use this formula: n/2[ 2a+(n-1)d] where a is the first no and d is the common difference

[jackal]

I had this formula in grade 6 but how you put this makes it so easy to understand

[TheHeavenlyRice]

With even less math, ignore the 200 initially.

1+199 gives an even 200, as does 2+198… and so on, all the way to the “center” number of 100.

All the possible numbers end on a clean hundred, so the answer MUST end in “00”. B is the only multiple choice answer that ends in “00”.

[narutoyzumake]

Арифметическая прогрессия. a1=1 b=1 S= (a1+an)×n/2 n=200

[qvkoqkr]

The legend says that Gauss’ teacher gave him this exercice when he was like 6 after he finished everything
And he found the formula because he was lazy and didn’t want to calculate every addition

[musicremixes]

THESE 1-MINUTE VIDEOS HELP MORE THAN MY 1HR OF ACTUAL MATH CLASS LOOOLLLL