Graph - 5: Breadth First Search (BFS) using Adjacency List | On Undirected Graph | On Directed Graph

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Solution:
- We'll take queue & boolean array
- We'll put starting index in queue & mark true for this index
- Now we'll poll one element from queue & fetch list for index. This'll show all neighbours connected to this index
- Now we'll add all elements which are not visited & insert into queue
- Do above until queue is not empty

Time Complexity: O(V + E)
Space Complexity: O(V)

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your "hey everyone" in the intro has got my roommates thrilled and they say hey everyone all the time now. We love your energy!

rheashajan
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Thank you so much!!!! I'm from Bangladesh... I am glad to find this channel. Highly recommended

PetBuddies
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Keep up the good work man. Need more videos on graphs😃

ClashWithSwap
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best bfs on adjacency list explanation! thanks

darrenhorwitz
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Very good work sir
Please we need more videos on graphs please make more videos fast👃🏻👃🏻👃🏻

AyushKumar-vhpg
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Amazing man! Im your Huge huge fan! Can you please help us in finding some larger roots of a large number in java and also how to effectively calculate large powers of a number. Please sir! I will really appreciate it. Thanx and regards.

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