Calculus 1 - Derivatives and Related Rates (9 of 24) Growing Sphere

I this video I will calculate how fast (dV/dt=?) the volume of the sphere is increasing if the radius increases at dR/dt=2cm/s.

Next video in this series can be seen at:

[Tomas-zvjs]

Sir. May God be upon your soul. You have helped, e solve a very complex problem to me and thus increased my grade but also increased my understanding of mathematics. Thank you. Like deserved

[monoman]

At last I am starting to understand. Thanks.

[physicsmaths]

sir i like your videos alot specially the way of teaching and explaining everything in detail .
i usually dont comment or like your videos because i play all videos simultaneously so dont get time to comment but i see all your videos step by step and gained a lot of knowledge from you.
Sir please make some videos on z-transform atleast some basics on it .
this is my first comment on youtube in 6 years :p
thank you sir for sharing your knowledge, most of the students just mug up some formulas and start solving numericals without knowing what the topic is about but you clear everything so easily i like it sir .
keep making such videos sir its is very helpful for all.

and please sir make some videos on z-transform
thank you sir, love and respect from india :)

[feriacientifica]

Something is telling me that I am going to use this concept in Electromagnetism, ...at least ! Thanks

[liaoyuqian]

Came from Kepler’s second law! Now I fully understood!

[niljujk]

Sir i have a question. Why did you multiplied dr/dt at last 😅😅

[rockyjoe]

Hmmm when we say dr / dt we mean the change of radius with the respect in change of time but in a very small time interval such as 0.001s, am I right? It's like instantaneous velocity right? ah and also when we say dr / dt at r = 4, usually we say at a specific time such t = x, but this time we said at r = 4, so I am confused at that point, can you help me visualize it?