filmov
tv
Find the area under sec^2x
Показать описание
This video is about finding the area between a trigonometric function and the x-axis.
Jeremy Klassen
area
integral
integration
area under a curve
area under a trigonometric function
Рекомендации по теме
0:04:05
Find the area under sec^2x
0:01:53
Find the area between the x-axis and the function y = sec^2 x over the interval [-pi/4, pi/4]
0:05:03
Find the area between y=sec^2x and y=x 1
0:03:08
Find the area of the region bounded by y=sec^2x and y=x+5 on the interval [0,1]
0:00:20
Integral of sec^2x
0:04:28
Find the area of the region. y = sec^(2)(x), y = 8cos(x), -π/3 x π/3
0:03:49
7 3d1 Sketch y=sec 2x
0:02:47
Find area of region enclosed by curves y = 8 cos x and y = sec^2 x [-pi/3, pi/3]. Areas in the Plane
1:14:43
LECTURE 20 INDEFINITE INTEGRATION
0:02:22
Find area of region enclosed by curves y= sec^2 x and y = tan^2 x [-pi/4, pi/4]. Areas in the Plane
0:06:38
Integral of sec^2(x), a totally unnecessary way!
0:00:16
This trick can make your rubik's cube 2x faster😱🔥#ytshorts#shorts#drcuber
0:08:31
Find the area the region bounded by y=cosx y=sinx the lines x=pi/4 and x=5pi/4
0:02:45
What are the vertical asymptotes of f(x) = sec 2x ?
0:05:16
What is the derivative of sec2x?
0:00:41
f(x) = sec(2x) find rate of change between 0 to pi/9
0:01:43
y=sec^2(x), y=2, x=-pi/4, x=pi/4 sketch the region enclosed by the curves and find its area
0:02:18
Integral of sec^2(2x - 74)
0:08:06
Area under the Graph of y = 1/(x^2 - 2x + 5)
0:00:56
Evaluate the integral ∫x sec^2x dx.
0:01:52
[IIT 1994] Prove that sec2x - tan2x = tan (PI/4 - x) when x lies between 0 and PI/4.
0:00:44
Integral of sec^2x dx || Integration of sec square x
0:01:01
Find y if y’ = 2x+5 & y(4)=36 #math #calculus #integration #bebright #bhagya #integral
0:00:33
Find the equations of all asymptotes for y= sec(2x)