Principle of Mathematical Induction (ab)^n = a^n*b^n Proof

Principle of Mathematical Induction (ab)^n = a^n*b^n Proof

[angelmendez-rivera]

One should be careful to note that this is not true for arbitrary n, only for natural n, and only if a, b are elements that commute.

[syesjohnny]

(a^n)(b^n)=ab^2 cuz a*a...a(len n)*b*b...b(len n)=ab*ab...ab(len n)

[pete]

At 3:00, after expanding (ab)^k+1, why did you use the part of the hypothesis along with what we are suppose to be proving?

[anushkatyagi]

Ye for abelian group k lye true h na only ??