LinkedIn Problem || Solving LeetCode Problems || Day 26 #programmingtutorial

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This code finds all the shortest paths from a starting word (beginWord) to a target word (endWord) by transforming one word at a time. Each transformation must result in a valid word from the given wordList. Here's a simplified explanation:


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Key Steps:

1. Setup and Check:

Convert the wordList into a set for faster lookups.

If the endWord is not in the wordList, return an empty list because there's no way to reach it.



2. Create Patterns for Neighbors:

Words that differ by one character are considered neighbors.

Create a dictionary (neighbors) where keys are patterns of words with one character replaced by * (e.g., h*t for hot), and values are lists of words that match the pattern.



3. Breadth-First Search (BFS):

Use a queue to explore paths starting from beginWord.

Track visited words to avoid revisiting and getting stuck in loops.

For each word in the current path, find its neighbors using the patterns and add new paths to the queue.

If the endWord is found, store the path and stop exploring further levels of the BFS (to ensure the shortest paths).



4. Return the Results:

Return all shortest paths found from beginWord to endWord.

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