Block A weighs 45.0 N, and block B weighs 25.0 N - Problem 5.34

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Consider the system shown in Fig. E5.34. Block A weighs 45.0 N, and block B weighs 25.0 N. Once block B is set into downward motion, it descends at a constant speed. (a) Calculate the coefficient of kinetic friction between block A and the tabletop. (b) A cat, also of weight 45.0 N, falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration (magnitude and direction)?
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Thank you I was about to pull my hair out

sharon
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thanks. hope you keep making these for us the calc gang

josejosepreso
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i don't get why we are considering the total weight 115N in the second part of the question and not the sum of the two 45N boxes?

astrar
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How is it even possible that this thing is going up? Did the cat use telekinesis? nothing about the problem has changed in part b except that block A got heavier. You would expect it to not budge. The problem even says it's "Set into downwards motion". Whoever comes up with these is a jerk.

nunyatoob