Conditional Permutation

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  1. Tambuwal Maths Class
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Комментарии
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He is a genius, I understand him clearly

FatimaMuhammadMusa-sb
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Wish you the best in your work of nurturing people.

AndrewMajokKuolKuot-vwhf
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Wish you could explain the separation aspect much more better
But good job and well done ❤😊

DelonisOkrah
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Hello sir. You have not told the students if the two LLs are distinguishable or not. If the two LLs are together and not distinguishable, then we have 3!x2!/2!=6. If the two LLs are distinguishable permutation will be 3!x2!=12.
Please think about this. That's the information missing from Further Math Project 2.

adeoluwaoluyinka
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I wish I had a lecturer like you😩, just some hours to the exams, thanks for this wonderful explanations

predictExpert
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4!/2!=12 ways of arranging the letters in the word HELL
Total minus 2LL together which is 12-6=6 ways

dicksonlukata
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Sir question how was the L 2 when there was three areas they can be put or place in even though the 2 L are identical

LvM_.
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Hello sir, what if in a situation where we have the word (ogbomosho) how can it be arranged?

taiyezubair