Integral of abs(x) in 44 seconds!

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bprp fast

[akshinbarathi]

IT SAID 44 SEC BUT THE VIDEO IS 43 SECONDS.SO HE IS A LEGEND

[jeremy.N]

This whole thing is equal to |x|*x/2 which is my favourite fact.

[NihilistEmier]

Alternate title : I integrated abs(x) in {2(π^e) + (cos(180)) } seconds !

[gourabjitbiswas]

I solved in just 4 seconds
∫ |x|dx=x|x|/2 + C

[abhinandanmaity]

I'm glad that you didn't forget to put +c in hurry😂😂😂😂😂

[davcaslop]

I'm just about of studying integrals, I'm so excited!!!

[RolandTheHero]

He did it so fast, I thought the video was sped up.

[MarcoMa]

I read that integral as 1 • 1 and immediately responded "x".

[lifehacks]

Forget about maths... The way he switches markers is the most intresting part hahha

[canaDavid]

Combining: sig(x)x2/2 + c, where sig(x) is the sign of x. Sig(x) is equivalent to |x|/x. Subst. |x|/x*x2/2+c
|x|x/2+c

[gggg-pvmr]

I littereally thought for the first 5 secs that he is speaking chinese

[NihilistEmier]

This video is 43 sec long.
And I am typing this while this video was uploaded 43 minutes ago :)

[SNoCappidona]

Math: integrate |x|
Engineering: integrate 2|x|-1
Hint: |x| is a piece wise function

[Alians]

The expression in the video has a negative coefficient if x < 0, otherwise positive. This is filled by |x|/x so -->

Answer can be written as: x|x|/2 + C

The |x-a|/(x-a) is a better useful way of settings conditions for positive or negative coeffecients.

[kannusingh]

Impressive
Good luck for your future, dear mathematician😁

[nilishabharadwaj]

That was frickin easy, why am I struggling with integration then ☹️

[pbj]

We can do better! sgn(x) is |x|/x or equivalently x/|x| (not for 0)
So for non-zero x, the integral can be written as 1/2*(|x|/x)*x^2= 1/2*x|x|+C

[Red-bzno]

Yea so... all I heard was “snake eggs”

[joyneelrocks]

U can just say that ∫|x|dx = sgm(x) * x^2/2 + C, where sgm(x) = sign of x = |x|/x, therefore ∫|x|dx = x * |x|/2 + C

[theimmux]

You could ditch the cases and express the integral as 1/2|x|x +C. I don't know how one could prove that tho.