#3 Principle of mathematical induction prove proof 1+5+9+...+(4n-3)=n(2n-1)

preview_player
Показать описание
Prove

Math Tutorials Links
Algebra
Foundations

Equations

Inequalities
Solve Systems of Equations by Graphing







TESTS

  1. maths gotserved
  2. 5^n-2^n is divisible by 3
  3. n^3 2n is divisible by 3
  4. 8^n-1 is divisible by 7
  5. 1/(1X2) 1/(2X3) ... 1/(n(n 1))=n/(n 1)
  6. n^2 less than2n
Рекомендации по теме
Mathematical Induction Practice 0:18:08

Mathematical Induction Practice Problems

Proof by Mathematical 0:07:32

Proof by Mathematical Induction - How to do a Mathematical Induction Proof ( Example 1 )

Proof by induction 0:09:23

Proof by induction | Sequences, series and induction | Precalculus | Khan Academy

#3 Principle of 0:18:43

#3 Principle of mathematical induction prove proof 1+5+9+...+(4n-3)=n(2n-1)

Induction Divisibility 0:20:35

Induction Divisibility

Mathematical Induction 0:10:04

Mathematical Induction

Principle of Mathematical 0:05:54

Principle of Mathematical Induction Inequality Proof Video

Proof by Mathematical 0:22:35

Proof by Mathematical Induction (Precalculus - College Algebra 73)

Mathematical Induction 0:13:06

Mathematical Induction

UNIT 3: PRINCIPLE 0:10:11

UNIT 3: PRINCIPLE OF MATHEMATICAL INDUCTION WITH EXAMPLE

Mathematical Induction Examples 0:12:14

Mathematical Induction Examples

How to use 0:20:45

How to use Principle of Mathematical induction to prove 3+6+9...+3n=3n(n+1)/2

Learn how to 0:07:08

Learn how to use mathematical induction to prove a formula

Matrices - Mathematical 0:04:32

Matrices - Mathematical induction

Mathematical Induction | 0:06:18

Mathematical Induction | Show that (n³+2n) is divisible by 3

Proof by Mathematical 0:13:24

Proof by Mathematical Induction | Principle of Mathematical Induction | Sample Problems | Part 1

Prove the following 0:11:03

Prove the following by the principle of induction | 1^2 + 3^2 + 5^2 +…..+ (2n-1)^2 = n(2n-1)(2n+1)/3...

Prove by the 0:10:41

Prove by the principle of induction | (1+1/3)(1+ 5/4)(1+7/9) …. (1+ 2n+1/n^2) = (n+1)^2

Prove by the 0:10:36

Prove by the principle of induction | 1.2.3 + 2.3.4 + 3.4.5 + …. + n(n-1)(n-2) = n(n+1)(n+2)(n+3)/4...

Prove by the 0:09:07

Prove by the principle of Mathematical induction | 1^3 + 2^3 + 3^3 + …. + n^3 == [(n(n+1))/2]^2

Intro to Mathematical 0:12:15

Intro to Mathematical Induction

Prove by the 0:10:45

Prove by the principle of induction for all n belongs to N | 1^2 + 2^2 +...+ n^2 = n(n+1)(2n+1)/6

Proof by Mathematical 0:12:38

Proof by Mathematical Induction | Part 3 | Pre-Calculus

Prove by the 0:12:46

Prove by the principle of Mathematical induction | n(n+1)(n+5) is a multiple of 3 | Mathematics

Комментарии
Автор

Yeah this method of induction is sooo much easier. The way the book shows it and the way I've seen professors teach it is for P(k+1): 1+5+9+...+(4k-3)+[4(k+1)-3] = k(2k-1)+[4(k+1)-3] and you start off with the two sides equal to each other and then work towards getting the RHS to look like the form of the RHS of the P(k) hypothesis. The goal is to get your RHS of your P(k+1) hypothesis to be (k+1)(2(k+1)-1).

BUT that way is much harder for sure, because it involves a lot of clever factoring and such. The method in the video should be valid because when I let k = 1 for k(2k-1)+[4(k+1)-3] = (1)(2-1)+[4(1+1)-3] = 1 + 5 = 6. Which is what I arrive at when I let k = 1 for your method of the RHS of P(k+1) hypothesis: (k+1)[2(k+1)-1] = (1+1)[2(1+1)-1] = 2 x 3 = 6.

chunkylover
Автор

Thank you very much. I couldn't get this in class, but now it's all clear. Thanks a lot!

rafaellima
Автор

Thanks m8, u explain it waaaayy better then ma teacher :D

TheFightmaster
Автор

thank you sir where is number 4 plz

seekerloka
Автор

nice video helps a lot thanks for the curse 

ujustfoundanobject