Related Rates - The Ladder Problem

This calculus video tutorial explains how to solve the ladder problem in related rates. It explains how to find the rate at which the top of the ladder is sliding down the building and how to find the rate at which the area formed by the ladder is changing. In addition, it explains how to determine the rate at which the angle formed by the ground and the ladder is changing with respect to time using derivatives and implicit differentiation.

Related Rates - Free Formula Sheet:

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Introduction to Limits:

Derivatives - Fast Review:

Introduction to Related Rates:

Derivative Notations:

Related Rates - The Cube:

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Inflated Balloon & Melting Snowball:

Gravel Dumped Into Conical Tank:

Related Rates - Area of a Triangle:

Related Rates - The Ladder Problem:

Related Rates - The Distance Problem:

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Related Rates - Airplane Problems:

Related Rates - The Shadow Problem:

Related Rates - The Baseball Diamond Problem:

Related Rates - The Angle of Elevation Problem:

Related Rates - More Practice Problems:

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Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

[pedrooreosg]

looks like im gonna be watching every single related rates video

[hockeylax]

He really posts this stuff for free...








You are my daddy. My super hero.

[cassied]

This was a perfect example question. It touched upon so much good stuff, in a practical and relatable problem.

[Undertakerfan]

We had a similar problem in class like this. It’s way more clear now. Thank you!

[briantaylor]

I just want to thank you for helping me in each of my math classes. Your videos are an invaluable resource, looking forward to being a paid subscriber soon!

[josiahchang]

He doesn't even say like and subscribe respect




Oh yeah yeah

[argoneus]

wow. impressive! 2 hour lecture compressed into clear explanation of 1 problem.

[kaitlynreyes]

these have helped me so much, both your videos on physics and calc are amazing!! thank you!!

[Adiam.Tekle.]

Your videos are so helpful. Thank you!

[coreygraham]

Literally used this to do my signature assignment in 13 minutes thank the maker

[lu-gcgm]

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[crazyjulianos]

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[johnnolen]

@ 10:39 "I'm gonna use sin θ."
Sin θ involves value(s) that you had to calculate; whereas cos θ involves only given information. Therefore recommend using cos θ because there's less opportunity for error.

[TheFarmanimalfriend]

The right triangle can be used to establish dy/dt. Ladder length is constant. Because of it we know y = 9 feet and we know dy/dt is negative (y is losing height, 8 ft). We also know -dy/dt = dx/dt and we know when y = 9, dy/dt = -16.00 feet/sec, so dx/dt = 16.00 feet/sec.
gravity = 32 feet/sec^2 or 9.8 meter/sec^2

[MrRgl]

everyone in the comments saying thanks make sure yall like the vid! 78k views and not even 1k likes...

[georgesadler]

MR. Organic Chemistry Tutor, thank you for an outstanding video/lecture on the Ladder Problem in Calculus One. This is an error free video/lecture on YouTube TV with the Organic Chemistry Tutor.

[imperiusss]

are you one day going to also teach statistics, cosmology, modern physics? thank you very much for this videos already!!!

[tracyvtv]

At 3:35, isn't 8 and 15 a constant as well? But we still took the derivative like normal, unlike Z, which became 0

[divinest]

i hope this doesn't come out in my test

[tellyhandler]

Bro got me through High School and now Uni lol






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