Equilibrium index of an array | GeeksforGeeks

This video is contributed by Harshit Verma

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[bipinsingh]

Bhai kitna ganda explaination h apka bikul v smj nhi ata aur kamse kam approach toh bataoo ki us qus tak kese approach karenge bs sidha line padhne lg jateh hoh solution ka aur woh toh first class ka bacha v krlega

[skasif]

Dear sir I want to practice competitive programmings, where do I have to register for the guidance or tutorials?? Please reply ASAP

[hamidansari]

Better approach is present on teck dose channnel

[codevlogs]

It will wrong for -7, 1, 5, 3, -4, 3, 1 but the some of -7, 1, 5, 3, -4, 3 is 1 and is equal to 1 and the above solution can't find this( first method)

[wecan]

int equilibriumPoint(long long a[], int n)
{

long long sum=0, leftsum=0;
for(int i=0;i<n;i++)
{
sum+=a[i];
}
for(int i=0;i<n;i++)
{
//long long t=sum-a[i];
sum=sum-a[i];
if(leftsum==sum)
{
return i+1;
}

leftsum+=a[i];
}
return -1;
}

[shubhd]

but the first method is giving wrong output for 2, 4, 4, 5, 4, 1

[dhananjayarjundavala]

Wasted 2 hours.. It will for only for some inputs..

[topthingwhichyoushouldkn]

i cant understand firstly you do same thing sum-=arr[i] and leftsum+=arr[i]
firstly you told us equlibrim point is that point in which left part is equal to right part and you compare the whole array by just giving - sign i cant understand