How to fix Modifying one element in a list of lists inadvertently changes al... in Python

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We're excited to share with you our newest video, "How to solve Modifying one element in a list of lists inadvertently changes all lists because they reference the same object. in Python". 🎥 This series is meticulously designed to arm you with knowledge 🧠 and skills 🛠️ to overcome frequent coding challenges.

Today, we will decipher 🔎 and resolve a common error faced by Python coders: the bit hard to solve Modifying one element in a list of lists inadvertently changes all lists because they reference the same object.. Here is a snapshot of the code of the video:

Troubling Scenario: ❗️

rows = 3
cols = 3
matrix = [[0] * cols] * rows
matrix[0][0] = 1
print(matrix)

Unwanted Result: 🚫
Modifying one element in a list of lists inadvertently changes all lists because they reference the same object.

Effective Resolution: ✔️

rows = 3
cols = 3
matrix = [[0 for _ in range(cols)] for _ in range(rows)]
matrix[0][0] = 1
print(matrix)

Desired Output: 🏁
[[1, 0, 0], [0, 0, 0], [0, 0, 0]]

In this detailed walkthrough, we will illuminate 💡 the underlying cause of this error, and offer a comprehensive explanation: Code1 uses the same list object repeated in each row, causing all rows to mirror changes. Code2 correctly creates independent lists for each row, allowing individual elements to be modified independently. 🎯

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