The Continuous-Time Unit Impulse Function 2/4

We continue examining the continuous-time impulse function in this video by exploring what happens when a continuous-time signal x(t) is multiplied by the impulse function delta(t). We see that the result of this multiplication is simply a delta function whose height/area has been modified by the value of the signal at the location of the impulse.

[saltylad]

This is explained much more clearly than my uni lectures. Thank you.

[ghostshadow]

Im trying soo hard to learn about signals in 1 day cos i have an exam tomorrow and the videos are helping

[lulua.]

This is great! I'm so grateful. I got a midterm tomorrow and this is helping so much.

[nalininadupalli]

Hello..
1. the height of each impulse in the impulse train is infinity. Only the area or density =1. Why is height and density used interchangeably?
2. If the height of impulse is multiplied with the finite "height" of the continuous time signal.. i.e. infinity* finite height (= infinity) then the result should also be impulse train.. but this is not being done... instead the density is multiplied by height...
3. How can density or area of impulse be multiplied with height of continuous signal? i.e. height and area are different quantities...Thanks a lot in advance!

[RolaEgan]

Thank you very much you make it easy God bless you. Rola

[sanjuambekar]

given the signal
x(n)=(6-n){u(n-6)-u(n-6)}make a sketch of x(n), y1(n)=x(4-n) & y2(n)=x(2n-3).