Differential Equations | Undetermined Coefficients Example 3

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We solve a second order differential equation using the method of undetermined coefficients.
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I believe the only thing that stays when we add up y''p and 4y is equal to 4Bcos(2x), I found this when I was solving beforehand and we found the same y'' and y, I think there was a small mistake there (and if there is, how can we say 4Bcos(2x) equals to -28sin(2x)? Does that mean there is no solution with our guess?)

(Edit: plugging 7xcos(2x) works so I guess my bad)

acarhankayraunal
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It's a small thing but the thumbnail is missing a -ve sign in front of the 28sin(2x)

pbj