Limit Comparison Test for Series

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The regular Comparison Test for Series was good, but it had a crucial problem: often we can't actually find an easy inequality despite being able to eyeball the dominant portions of a series. The Limit Comparison Test lets us cover these days by comparing the series to one who terms - in the limit - differ by a nonzero ratio.

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This video was created by Dr. Trefor Bazett, an Assistant Professor, Educator at the University of Cincinnati.

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I swear this is one of the best maths and physics channel to exist on YouTube.

arpanmukherjee
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2:12 the nominator of the last expression should be 2n^3+2n^2.

hikmatullahpakhtoon
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You are getting me through University. Thank you so much for this series. No pun intended

brayanmuniz
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You are my all-time life saver. I wish I found your videos at the beginning of the semester!

yehuawang
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2:34 exactly what I was asking at that moment. I like your style of presentation and way of thinking <3

arinoba
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the best tutorial on Youtube. thank you.

thapaharis
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amazing explanation in just 5 minutes!!

mathCS
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Isn't the numerator supposed to be 2n^3+2n^2 instead of 2n^3+2?

olefshn
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You could also apply PFD (partial fractions) and then perform the integral test.

mauriciobenjaminmossi
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What happens with a negative answer? Do they do the same thing but in opposite directions?.

Mortgageman
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Yeh banda pure maje leke padhata hai😂👏
English translation- This teacher teaches with full pleasure😂👏

funindu
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this man has the prettiest nose i've ever seen

amanda-uxeq
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0:53 In such a simple case, could I just set my b_n to something obviously larger than the a_n; say, b_n = 1 over n squared ?

AeroCraftAviation
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baby is calling behind 1:20, get noticed..

cokcury