Equations of Motion using Calculus - for constant acceleration | PHYSICS | CBSE | IIT JEE | NEET

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Motion in One - Dimension (Class XI) for CBSE, JEE and NEET

Derivation of the three equations of Motion (under constant acceleration) using calculus

v = u + at
s = ut + (1/2)at^2
v2 - u2 = 2as

Learn how to apply differentiation and integration in Physics

v = dx/dt

a = dv/dt

a = v dv/dx

Slope of v-t graph gives acceleration

Area under v-t graph gives displacement

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All our content is organised there subject wise and chapterwise along with assignments, tests and doubt discussion forum?

COACHenggu
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It is really good method to understand easily calculas in 3 equation. Thanks for this video.

yogeshvaidya
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The process you explain is much innovative and useful for students

physicssteppingstones
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Thanks a lot from the core of my beart just a small suggestion please elobrate those terms further which u imagine students know because some of the students like me visit just to see how a=v dv/dt....furthermore thanks a lot for ur wonderful explanation

bintihawa
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Thank you so much sir Your explanation is amazing

Santoshsingh-mbli
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Very nice and explanatory thank u so much

lakshmisridhar
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puneetkaur
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CHAMAR-GIDH
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debojitdas
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saleemmalikk
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bossgaming.
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PunjabiViralVideos
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Nyc one...make sm more on integration and differtciation...✌

ksvishnuvarma
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Nice video sir. It's very helpful

perfectawareness
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MandeepKaur-menn
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Can u provide us with the basics of integration sir?

ayan
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thnxx ....thanx a lot

AtifKhan-nlzv
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RehanKhan-gyrp
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shalendrasolanki
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