Calculus In The REAL World!!

How To Solve Projectile Motion Problems Using Calculus!! #Math #Science #Velocity #College #NicholasGKK #Shorts

[justplay]

Its a kinematic equation 10t is simply V(initial)*t + 50 is Y(initial) -1/2gt^2 (g is acceleration due to gravity which is -9.8)

[tunistick]

our exams be like "calculate α the angle between Vi and the horizontal plane and β the angle between Vf and the vertical plane"

[paranoyd]

y(t) = y0 + v0t + (1/2)at^2 where y0 is the initial position (50 in this case), v0 is the inicial velocity (10), and a is the acceleration (-g in this case)

[NotYuji_weeb]

I was always bad at math but i learn something good always from you

[Ther]

Uh huh, yep. That's what I was thinking.

[jazzle]

so the ball is moving 10 meters per second even time is still zero? doesn't make sense to me. How can the ball have a velocity when it is at rest.

[draculq]

-4.9t^2 represents gravity in meters 50 is the starting position so 10t is the initial velocity just by looking at the equation

[NoosaHeads]

Isn't it a question of dy/dt being slope "0" and wouldn't that be a 0= -9.8t +10 giving 9.8t =10 ie T= 10/9.8 ie approx 1.1 seconds?

[Bellaisbald]

Is more simple to say 10T is = 10 meters per second 😅

[Nxck]

This isn't real world, you need to find that y(t) from geometry or sth

[tahliameadows]

How is the velocity function equivalent to the derivative of the original y function that was given befor you found it? I dont understand

[rossfriedman]

How does it start at a non zero velocity if it's falling off a ledge?

[beinganangeltreon]

ok, this is kind of comical, but what could you ever do to a moving object that would take a negative velocity or time (film backwards), and then multiply it with another negative, to get an imaginary number, one possibility is towards the screen could be positive, and deeper into the screen as negative, if the entire moving thing were receding into the screen then it would be -4.9t if we treat 4.9T^2 as negative as its towards earth, oops, t^2 is automatically 4.9i from the negative exponent as a ^2, but the thing is, if you derive that 4.9i you either get -4.9 or there's some other weird thing about removing a unit amount from the exponent, so i just goes to zero, but if you do that you still have just regular 4.9, or maybe you have -4.9, but if you have -4.9 then gravity(9.8) is half force, or its only 4.9t, and goes half velocity, but if either of those is true then, somewhat incredibly making Y=0 then I still get rid of that 4.9 and still have 10 as the velocity. and, that's what not passing calculus but getting the occasional test question right. I really like math though, it's fun, I'm just technically ignorant. Study math!

[Iamrich]

How did u know that you have to take the derivative to find velocity

[backwashjoe]

Where did you get the units of m/s at the end? There were no units of distance specified up to that point.

[daco-shitpost]

just use x = x0 + v0t + at^2 / 2, the coeficient next to t^2 is -g/2, the coeficient near t is v0, the remaining coeficient is x0 (height)

[F--kyouTony]

Love mathematics, but the last class I took was intro to stats. Ummmm, what?