Solve PDE via an integrating factor

[TGears]

very concise yet elaborate way of explaining a very useful way to incorporate integrating factors. You have an elegant way of teaching. Keep it up!

[StudioFrenzy]

You have saved my degree! My PDE lecture notes are rubbish. They assume so much knowledge and don't teach anything. The lectures consist of 2 hour proofs most of the time that don't help at all towards my understanding. Thanks Chris!!!

[Jkfgjfgjfkjg]

Very nice. Thank you for doing this! Humanity desperately needs more people like you.

[tacobellas]

Great playlist, super explanations! Also very good for refreshing on previously taken PDE courses. I wish this was around when I was taking my PDE course. Thank you for making this!

[DrChrisTisdell]

Thanks! The method does generalize to other linear problems. For example, think about
a(t)u_t + u_x + k(x)u = 0. Here the integrating factor would be an exponential whose exponent is the integral of k. Can you see any more generalizations?

[DenisKevin]

your videos might very well save my semester. god bless you

[Peter_]

I don't even need to study this particular type of PDEs, but I found them so interesting and rewarding that I watch them anyway. xD
My course immediately went to 2nd order PDEs for some reason.

[at]

Thanks Chris. Nice explanation. By the way can you tell how you build your video? Hoy you combine the images? Did you use two cameras?? What kind of software did you use. 

[liquidstl]

Great Video Dr.Tisdell! I am curious though- which types of PDE can an integrating factor solve ( aside from this one obviously)

[giannisniper]

would it be the same if one chose the integrating factor to "unify" the u term with the u_t term?

[BlakeCreate]

How did you use the v to go from (ue^7x) piece to ue^7x = f(x-Ct)
And how did you then make the e^7x negative?

[brandonkeeling]

what if the u_x term is negative? Then, the integrating factor would not work because of the reverse product rule...