Binary Search in Java by Deepak (Hindi)

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SmartProgramming
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tomorrow is my ICSE 10th standard board video for giving me 15 marks

shreyasgowda
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You have given me 10lpa job So infinite thanks to you

nishiketwadile
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Its really a blessing to have someone Who is more dedicated in Educating others! Thank you so much for all your Efforts Sir, Smart Programming is definitely a One-Stop-Shop for Java (SE + DSA + Problems). Learnt a lot from you, You turned a ME into a Java Developer!
Keep Booming Sir 🙏

sniper.x_x
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Java becomes interesting only because of you, Sir. I am very grateful to you. Keep uploading more tutorials.
Regards,
Nidhi

shreeprakashdwivedy
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this video is so aweswome sir mera computer marks 2021 boards ke jo aayenge woh mai aapko dedicate karunga aap mere bhagwan ho sir

thatmahindralover
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Bohot accha lagata hain jub koyre problem hoo orr uska solution upke channel pe hota hain.

allaboutit
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sir very nice Explanation ..subscriber from Hyderabad

maheshreddyjanga
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I just wanna say that you are an awesome teacher cause i seriously understood very bit of concept
Thank u

ishitagupta
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Watching after 1 yr of upload, nicely explained, very much impressive, now I will complete my java from your channel

MultiHarsh
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Awesome sir..at first I was confused about this binary..you explained it so well ...that I have no confusion.. thank you..

SanjaySingh-tzhn
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Sir thank you so much, sb log sirf practically btate hai, aap ne theory or pratical dono bataya, that helps a lot

shekharsuman
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Sir you make programming very easy...
Well done sir

imnankaka
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Sir Please aap aise hi video banate rhiye
Bohaut help ho jati h sir
Mera kuch din baad exams h
aur main fully prepared hun...
Thanks a lot sir...

ScottechIndia
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Sir, im becoming your fan.everyday 2 videos sure as my daily routine. i have some questions and enquires please ans me.
1: please do all searching technique including hashing
2: explain about big O, and time and space complexity
3: All data structure logical implementation (optional: using library function)
waiting for your answerss....thank you :)

krishnamohanty
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name this method :-


public class ok6 {

public static void main(String[] args) {
int [] a = {1, 3, 5, 7, 9, 11, 13, 15};
int li=a[0];
int hi=a.length-1;
int mi=(li+hi)/2;
int item=11;
int temp=0;
while(temp==0){
if(a[mi]==item){
System.out.println("item is at "+mi+" position.");
temp=1;
}
else if(item<a[mi]){
mi=mi-1;
}
else{
mi=mi+1;
}
}
}
}

tainatcoding
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Aapke samjhane ka tareeka bahut hi accha hai...I believe even a dull student can get your teaching.. Great work! KUDOS!

TheRockerAnuj
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After tommorow is my ICSE 10 standard board for giving this vedio😊

vaishnavishukla
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Thanks sir I have been watching you videos for 1 year

brishatroycc
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Thank you sir ....it's very helpful

anushkaarya