Binary search in 4 minutes

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Binary search in 4 minutes.

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another day, another person's semester you just saved

theatticbywik
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CS UG student here, you are precise and to the point which makes you different from rest of the creators

harshvardhansingh
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Best video on binary search I've found, straight to the point with well made animations. Thanks a lot Michael!

NeerajSamshette
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Thank you for using a black background and white text. All of your older sorting algorithm videos were really helpful.

nalskipper
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Damn. I am commenting a bit late but man it's people like you who help me keep on coding and not giving up. Thank you! Amazing content.

amitos
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u r singlehandedly making algorithms easy for people keep it

duelingo
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Your code is so simple and easily understandable, it helped a lot. My professor had 3 slides on it, very yuck. Thank you so much!

theanamex
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such a great explanation, I love your calmness

glenn
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Ur the goat bro I just watch ur vids 1 hr before the exam and covered the entire 5 months syllabus, 🔥🔥

sudhirms
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reviewing for a data structures quiz rn, this was exactly what i was looking for! 💪very clear and helpful explanation :3

Czarcasm.
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Oh this makes it so much easier i was watching the visualisation but i just get confused lol since i am not very perceptive thank you this helps a lot

Anonymous-rimk
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Cool stuff Michael! Keep up the great work!

yorgodev
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Please please please keep making videos, I watch your videos everyday, you make my day, thank you

okok-sccx
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I watched previously the video where you explain the Big-O Notation, in it you showed ant the end that in a "IF -> ELSEIF -> ELSE" the time complexity would be O(n^2).
At 2:47 there was an "IF -> ELSEIF -> ELSE" why is the time complexity in this case O(log n) and not O(n^2)?

DavidZapata-qn
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0:35 generally it will be rounding down since int always kind off round down by default in more languages

Neb_Explains
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Him: “quick sort=pivot”
Me: “WHILE HE HID IN RADIO WE PIVOTED TO VIDEO 🗣️💥”

SunsetsOverBatteryCity
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Great Explaination! Could you make a video on Linear Search is well?
:)

t_ahmad
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hey, try median bucket sort, its 2n log n, ie, first linear median search O(n) then split the elements to two buckets, repeat for sub-buckets

Jkauppa
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Just a quick question, after finding the average of index, if that mid position happens to land on the target index, does the search stop and the target is found?

techytech
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Curious if it would behoove the algorithm to check if either left, right, or mid is the answer

sweetphilly