Work Energy Problem - Sliding Down a Ramp

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Physics Ninja looks at a work-energy theorem problem.
We calculate the distance on the ground that a block slides using the work-energy theorem.
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14:02 is it okay if i said
fd=∆k
Which means Mgd=1/2mv^2
Which means

gd =1/2v^2


Then substitute with the values i know
To get d

moon-ecus
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Thank you so much Physics ninja I have a similar 7 marks question, now I know how to do it.

SILE
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When you substituted d1 for h/sintheta, you cancelled mgsintheta to mgh but I don't think that's correct because sin theta and h/ sin theta are not being multiplied. Sin is a ratio i.e, it's sin OF theta. Eng is not my first language but I hope you understood my doubt. Could you please answer if I'm missing something?

pleuvoirzz
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There's one I'd like to see.

A block of mass of 4 kg being pulled up a frictionless ramp by a constant force of 6 N. The ramp is 5 m high and 75 m long. If the block has some initial velocity, let's just say 3 m/s, what is the speed at the top of the ramp? I've made-up all these numbers. This isn't a homework problem or anything.

fizixx
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Would that be easier for the ramp part to calculate the resulting/net force and then calculate work done on the ramp as a product of the net force over distance1 ?...thanks for ur videos!!

sergeyborodin
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How about repeating using conservation of mechanical energy?

klong
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what if there is another ramp on the end

angeloorteza
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I’m getting 14.147 m by using a different method that’s worked in the past (energy transformations). Weird.

ytman-lqmj