Green's Theorem

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In this video, I present an example of Green's theorem, which is a very neat formula that allows you to calculate line integrals of any 2D vector field by converting it to a regular double integral. I also explain why it intuitively makes sense, by comparing macroscopic rotations with microscopic rotations. Enjoy!
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Im a french student a love watching maths teaching in english.
Thank you for your videos

jessicatambo
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I was looking for a way to remember Green’s Theorem. It turns out that “Quixotic Peyams” is a great way to memorize this, Tq!!!

kevinfung
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Hi dr Peyam. I followed a freshman course back in '86, (Vector calculus, textbook by Marsden & Tromba) The neat thing was that they had a picture of a golf player walking around the edge of the green, circumventing the hole. That made me remember the theorem and its name until now.

koenth
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Is there anything like “Peyam's theorem”?

soumyachandrakar
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Awesome videos. Can you make a video about Green functions? Thanks!

simewn
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The example of whirlpool makes everything clear.
Thank you sir

RajeshYadav-reig
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How does one prove Clairut's Theorem (ie the symmetry of second partial derivatives) using Green's theorem though? Any chance you can do a video on that Dr. Peyam?

ummwho
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Happy Belated Thanksgiving and Black Friday Dear Sir.

shubham
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but inorder for the integral of the conservative field to be 0 the shape has to be differentiable

tahamahha
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Wow, the title of the video is written with Green pen

MicheleCaine
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Circulation? that sounds suspiciously like physics

borg
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I know x greater than 0 but how x less 1 where is 1 please answer me

mohammadalkhateeb
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i Alice to Bob Gauge Holographic Transform
Pardon me...Green's Theorem
…smells
gauge coordinate transformation orbits X*Y*Z(c*t)

……….Bob and Alice sharing a transformed coordinate system with degree_^n = 3 degrees of freedom entangling Choice(n, r), n = 4 and r= 3, P3 permutation group factorial sphere's surface coordinates (X, Y, t) .... 't' is the closed boundary edge speed of light distance converted to surface meters distance bound by quadradic formulae X^2 + Y^2 = -Z^2 solvable equation points ( (X, Y, t) } constrained by zero time mod(Pn) = 0 Schwarzschild solutions -Z^2 = Pn * t^2 surface integral with boundary characteristic Pn point solution set |{ {(X} {Y} { Pn * c * t) }| = 3

abdonecbishop
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