5.17 | Consider the 52.0-kg mountain climber in Figure 5.20. (a) Find the tension in the rope and

Consider the 52.0-kg mountain climber in Figure 5.20. (a) Find the tension in the rope and the force that the mountain climber must exert with her feet on the vertical rock face to remain stationary. Assume that the force is exerted parallel to her legs. Also, assume negligible force exerted by her arms. (b) What is the minimum coefficient of friction between her shoes and the cliff?

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[GlaserTutoring]

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[Maatkare]

So thankful for your videos! Having a step-by-step solution is so beneficial, if I get stuck somewhere, or can't find my mistake. Or, even if I have no idea where to start. Really appreciate them, thanks so much!

[Caulin_]

Dang, I've watched like 3 of your vids now

youre great :)

[ghghghgh]

you saved my sanity with this video. Thank you so much :)

[farisalfaris]

Thanx.
But in 16:11 it is the static coefficient of friction not the kinetic !

Coz even when she is stationary (and that is what you built your solution on) the static friction force is the for which is holding the climber from slipping.

[benmiddleton]

for part a why would you not include the normal force or the friction force

[ghan]

This helps me a lot thank you so much !

[mitrasalchemy]

So, FL is not the normal force on the leg?

[ryland]

how come the tension on the rope is more than the tension would be if she were to be hoisted solely by the rope which is ma=(52)(9.8)=509N. isnt the rope losing tension due to her using the wall to support some of her weight rather than the rope gaining more tension? she is stationary, using force on the wall to support her legs, and not being pulled down by anything but gravity. what am i missing?
ty for the vids, helpful as always!!

[DanBalicky]

this video helped me immensely, this problem was making me want to smash my head against a wall

[jj-lrpi]

im a little bit confused, why is friction kinetic and not static? I thought that friction is static whenever an object/person is stationary because there's no movement