implicit differentiation chain rule and quotient rule combined | tan(x - y) = y / (1 + x^2)

Implicit Differentiation Chain Rule and Quotient Rule Combined | tan(x - y) = y / (1 + x^2)
Implicit Differentiation Chain Rule and Quotient Rule Combined | tan(x - y) = y / (1 + x^2)
If I asked you what topic of calculus you found hardest what would it be?
Would it would be - Implicit differentiation ,Chain rule, Product rule, Quotient rule or maybe dealing with Trig functions? What happens when you put a bunch of those things into one problem? It gets pretty tricky. Well I wanted to show you an example of how to deal with all these different things when they're all wrapped up into one problem. Because I agree it can be really hard to kind of keep track of the different steps of that process and how to apply all those different things to solve just for dy/dx in one single problem.
Be sure to stick around to the end of this video because I assure you I can help make it a little bit easier for you. Hopefully set you on a path that you feel a little bit more comfortable solving problems like this on your own in the future. If that sounds good to you be sure to stick around to the end of the video and without further ado let's just jump right into it.

The Problem is
Find dy/dx by Implicit Differentiation
tan(x - y) = y / (1 + x^2)

Chapters,
0:00 Introduction
0:58 The problem
1:13 Start to find the derivative of the equation
1:38 Applying chain rule to the left part of equation
3:33 Applying quotient rule to the right side of the equation
6:08 Simplification
9:29 Move dy/dx terms in one side of equation
11:19 Simplification
12:48 Solve for the problem
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#jakes_math_lesson #implicitdifferentiation #quotientrule

[JakesMathLessons]

0:00 Introduction
0:58 The problem
1:13 Start to find the derivative of the equation
1:38 Applying chain rule to the left part of equation
3:33 Applying quotient rule to the right side of the equation
6:08 Simplification
9:29 Move dy/dx terms in one side of equation
11:19 Simplification
12:48 Solve for the problem