CARNOT CYCLE: efficiency of carnot cycle

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in this video derive an expression for efficiency of Carnot cycle. it is an ideal cycle , it have four process like constant temperature as well as isentropic process.
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Very nice sir is video ke Carnot cycle ka sabhi step samagh AA gaya good teaching experience, you are great 👍👍👍

pavanbasor
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Thank you bhai video k liye. Itna Achha mujhe sach me smjha tha apka video Bhot Achha h.

mohammedhubaibshaikh
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Channel bahut achha hai
Video se badi help mili sir

rishabhsingh
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Nice sir....mast samjhaye aap..wah..mazaa Aa gaya gurudev

RahulKumar-ncnn
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Thank you very much, Sir. Very nice video
I will use this in my exam which will occurred in tomorrow 26/08/2019

RakibulHasan-hpyn
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Very simple explanation in comparison to other 😍😍😍😍😘😘

xavier
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Bhai bhout bhadhya explain kiya h thank you bro very very thank you

princekuthar
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Thank you sir it was very good explanation of such a complex topic in a small time

subhankarmandali
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Wah! Sir
Kya samajay hai..
Fully concept clear.

parthchavda
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Thanks sir this video help me for my u very much sir

SMani-jmhx
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video was very helpful for me....thanku so much sir

manteshyadav
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thank you so much sir this video is veryn helpful thank you so much

nikhilsonera
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Thanku so much sir.. For this explanation

priyasingh
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Thank u so much sir it was easy to understand

muhammadfarhan
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Sir mja aagya aap bought Acha padte hn

meditativemindsco.
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Lel... I ve bck in 3rd sem.. And I cnt affrd tuition teacher... So I am here😂😂😂😂 FML

nbhage
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U =q +w
At Constant temperature, U=O
q=-w and dw=-pdv
p=nRT/V, when you put this value in above equation, get
q=nRTln V2/V1

RajivKumar-xbfi
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plz post the video for finding the efficiency of DUAL CYLCE also plzzz..these videos are really helpful as they r short n crisp to the point...

kritigupta
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Sir ur wonderfull explained for these derivations, & formulae..
I can understand for these topic .
Plz sir, I request u many vedios u can made for numericals, for Carnot thm, Rankine cycle, vapour cycle, .I say this will help us in Exam.We are proud of you making a good explaination, You are doing really well, we support you👍👍😊😊

tejaskumbhar
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Thank you sir
Now I completely understand it

sillysophie